Using the quadratic equation formula:
x = -3 - the square root of 3 or x = -3 + the square root of 3
y = x2 - 6x + 2 y = x2 - 6x + 9 - 7 y = (x - 3)2 - 7
The quadratic expression x2+6x+8 when factorised equals (x+2)(x+4)
x = 2 and x = 4
hyperbola
You don't have an equation there.
y = x2 - 6x + 2 y = x2 - 6x + 9 - 7 y = (x - 3)2 - 7
x2 + 6x = 16=> x2 + 6x - 16 = 0=> x2 + 8x -2x - 16 = 0=> (x+8)(x-2) = 0=> x = -8 or x = 2So, the solutions of the quadratic equation x2 + 6x = 16 are -8 and 2.
A quadratic equation. If you wish to solve for x, you can do so as follows: -x2 + 6x + 7 = 0 x2 - 6x - 7 = 0 (x - 7)(x + 1) = 0 x ∈ {-1, 7}
The quadratic expression x2+6x+8 when factorised equals (x+2)(x+4)
hyperbola
x = 2 and x = 4
You don't have an equation there.
Equals anything... x is a variable. If that equation was set equal to zero then you could solve for x, but that is not what you have asked.
x2+6x+9 = x+3 x2+6x-x+9-3 = 0 x2+5x+6 = 0 Solve by factoring or with the help of the quadratic equation formula: (x+3)(x+2) = 0 Therefore: x = -3 or x = -2
x2 + 6x + 9 = 81 x2 + 6x = 72 x2 + 6x - 72 = 0 (x+12)(x-6) = 0 x= -12, 6 (two solutions)
x=1 and x=-7 are.
Line of symmetry: x = 3