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You don't have an equation there.

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13y ago

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Related Questions

What are the roots of the polynomial x2 plus 3x plus 5?

You can find the roots with the quadratic equation (a = 1, b = 3, c = -5).


What are the roots of the quadratic equation x2 plus 14x plus 45 equals 0?

The roots are: x = -5 and x = -9


Roots of the equation x 2 plus 5x plus 7 equals 0 will be?

There are no real root. The complex roots are: [-5 +/- sqrt(-3)] / 2


What 2 values of x are roots of the polynomial x2 plus 3x-5?

You can find the roots with the quadratic equation (a = 1, b = 3, c = -5).


What is the answer to the equation 2x2 - 10x plus 7 equals 0?

The roots of the equation are [5 +/- sqrt(11)]/2 = 4.158 and 0.842


What is x squared minus 2x plus 5 equals 0?

It is a quadratic equation with one unknown variable, x which has no real roots.


What are the roots of the quadratic equation y equals 2x2 plus 3x-20?

2x2 + 3x - 20 = (x + 4)(2x - 5).


Use the discriminant to determine the real roots How many roots are in this problemx2 plus 2x plus 5 equals 0?

x2 + 2x + 5 = 0 is already in the form ax2 + bx + c = 0 so to find the discriminant, D, you use D = b2 - 4ac Then if D is greater than 0 the equation has 2 real roots; if D = 0 the equation has one real root and if D is less than 0 the equation has no real roots. So to check this we work out D but we need to know what a, b and c are. From the equation we can see that a = 1 b = 2 c = 5 so putting these values in to find D: D = (2)2 - 4(1)(5) = 4 - 20 = -16 so the equation x2 + 2x + 5 = 0 has no real roots.


Is 3x plus 5 an equation?

No, an equation needs an "=".


How do you complete a square math problem?

It often helps to take square roots on both sides of the equation. However, solutions to the original equation may be lost - it is often convenient to put a "plus or minus" sign so as not to lose solutions. Example: x2 = 25 Taking square roots: x = "plus or minus" 5


Which equation has the solutions x equals 1 plus and minus the square root of 5?

The equation that has the solutions ( x = 1 \pm \sqrt{5} ) can be derived from the quadratic formula. Specifically, these solutions can be expressed as roots of the equation ( x^2 - 2x - 4 = 0 ). When simplified, this equation matches the given solutions, as substituting ( x = 1 \pm \sqrt{5} ) satisfies the equation.


What is the value of k when the equation x squared plus 2kx plus 10x plus k squared plus 5 equals 0 has equal roots?

Using the discriminant of b^2 -4ac = 0 the value of k works out as -2