You don't have an equation there.
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The roots of the equation are [5 +/- sqrt(11)]/2 = 4.158 and 0.842
2x2 + 3x - 20 = (x + 4)(2x - 5).
x2 + 2x + 5 = 0 is already in the form ax2 + bx + c = 0 so to find the discriminant, D, you use D = b2 - 4ac Then if D is greater than 0 the equation has 2 real roots; if D = 0 the equation has one real root and if D is less than 0 the equation has no real roots. So to check this we work out D but we need to know what a, b and c are. From the equation we can see that a = 1 b = 2 c = 5 so putting these values in to find D: D = (2)2 - 4(1)(5) = 4 - 20 = -16 so the equation x2 + 2x + 5 = 0 has no real roots.
No, an equation needs an "=".
It often helps to take square roots on both sides of the equation. However, solutions to the original equation may be lost - it is often convenient to put a "plus or minus" sign so as not to lose solutions. Example: x2 = 25 Taking square roots: x = "plus or minus" 5