The expression is (x + 8).
It's not an equation, it doesn't ask a question, and it doesn't need an answer.
(The question your teacher asked you: "How would you write this expression ?"
is a fine pedagogical question, but not a mathematical one.)
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Let the number be represented by x. The product of a number decreased by 3 is (x-3), and increased by 4 is (x-3+4) = (x+1). According to the given condition, this product is equal to 8. Therefore, the polynomial equation representing this condition is: x+1 = 8.
Equation 1: y = 8/x => xy = 8 Equation 2: y = 7+x Substitute Equation 2 into Equation 1: x(7+x) = 8 x2+7x-8 = 0 => (x-1)(x+8) = 0 x = 1 or x = -8 Substitute these values into Equation 2: When x = 1, y = 8 When x = -8, y = -1 The coordinates are (-8,-1) and (1,8)
y x 8
Without an equality sign the expession given is not an equation. But if you mean 8 = 42x then the value od x is 8/42
x=3 For the equation x + 8 = 11, only one step is required to solve for x Subtract 8 from both sides of the equation to get the x term by itself. 11-8=3, so x=3