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In real numbers there is no square root of -4x2
However, when using complex numbers where √-1 = i, then:
√-4x2 = 2xi
If you were asking, for example, with regard to the difference of two squares, eg y2 - 4x2, then you are actually finding the square root of 4x2 which is 2x, giving:
y2 - 4x2 = (y + 2x)(y - 2x)
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Earn +20 ptsQ: What is the square root of -4x2?
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What is the answer to the square root of 4x2 times the square root of 36x?
(√4x^2)(√36x)=2x(6√x)=12x√x
How do you factor 4x2 plus 1?
(2x - i)(2x + i)where i is the square root of negative 1.x = 0.5i, -0.5i
Square root 24x4 divided by square root 3x?
Sqrt(24x4)/Sqrt(3x) = Sqrt(24x4/3x) = Sqrt(8x3) = Sqrt(4x2*2x) = 2x*sqrt(2x)
X² plus 20 equals 4 a. square root of 24 b. -4 c. square root of 24 with a plus minus before it d. no real number ans.?
b. -4x2+20 = 4x2 = 4-20x2 = -16x = -4Note that -42 = -16 but (-4)2 in brackets = 16
Find the real roots of 4x²-9 equals 0 if any?
Simple...4x2-9=04x2=9x2=9/4x=+3/2 or -3/2Missed a step. :)x2=9/4x2=3/2x= square root of +- 3/2
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