In real numbers there is no square root of -4x2
However, when using complex numbers where √-1 = i, then:
√-4x2 = 2xi
If you were asking, for example, with regard to the difference of two squares, eg y2 - 4x2, then you are actually finding the square root of 4x2 which is 2x, giving:
y2 - 4x2 = (y + 2x)(y - 2x)
(√4x^2)(√36x)=2x(6√x)=12x√x
(2x - i)(2x + i)where i is the square root of negative 1.x = 0.5i, -0.5i
Sqrt(24x4)/Sqrt(3x) = Sqrt(24x4/3x) = Sqrt(8x3) = Sqrt(4x2*2x) = 2x*sqrt(2x)
b. -4x2+20 = 4x2 = 4-20x2 = -16x = -4Note that -42 = -16 but (-4)2 in brackets = 16
Simple...4x2-9=04x2=9x2=9/4x=+3/2 or -3/2Missed a step. :)x2=9/4x2=3/2x= square root of +- 3/2
(√4x^2)(√36x)=2x(6√x)=12x√x
x = square root of 3.
Only if the term under the radical (square root sign) can be simplified to a rational expression. For example, √(4x2).
(2x - i)(2x + i)where i is the square root of negative 1.x = 0.5i, -0.5i
Sqrt(24x4)/Sqrt(3x) = Sqrt(24x4/3x) = Sqrt(8x3) = Sqrt(4x2*2x) = 2x*sqrt(2x)
b. -4x2+20 = 4x2 = 4-20x2 = -16x = -4Note that -42 = -16 but (-4)2 in brackets = 16
4x^2 = 12 Divide through by '4' x^2 = 3 Square root both sides x = +/-sqrt(3)
None, it involves the square root of a negative number so the roots are imaginary.
4x2 - 30 = 34 Add 30 to both sides 4x2 = 64 Divide both sides by 4 x2 = 16 Take the square root of both sides: x = 4 or -4
Simple...4x2-9=04x2=9x2=9/4x=+3/2 or -3/2Missed a step. :)x2=9/4x2=3/2x= square root of +- 3/2
Reading this as: 4x2-6=2x2 This implies that: -6=-2x2 3=x2 x=sqrt(3) and x=-sqrt(3) So x can equal plus or minus the square root of 3
4x2-30 = 34 4x2 = 34+30 4x2 = 64 x2 = 16 x = 4