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Your question has no operator between -7q and 2.
7q+13 = 52 7q = 52-13 7q = 39 q = 39/7
The cube of the binomial ( (4k - 7q) ) can be calculated using the formula for the cube of a binomial, which is ( (a - b)^3 = a^3 - 3a^2b + 3ab^2 - b^3 ). Here, ( a = 4k ) and ( b = 7q ). Applying the formula, we get: [ (4k - 7q)^3 = (4k)^3 - 3(4k)^2(7q) + 3(4k)(7q)^2 - (7q)^3. ] This simplifies to: [ 64k^3 - 84k^2q + 147kq^2 - 343q^3. ]
To simplify the expression (2q + 10 + 7q), combine the like terms. The terms involving (q) are (2q) and (7q), which add up to (9q). Therefore, the simplified expression is (9q + 10).
17p+17q+p-7q-6p = 12p+17q
7q = 21 q = 3
7q+13 = 52 7q = 52-13 7q = 39 q = 39/7
Solving by elimination: p = 3 and q = -2
14p + 14q + p - 7q - 6p = 9p + 7q
welll 7xq = 7q..xq would be 7q squared
8 + 5p + 7q + 9 + 3p Reordering: 8 + 9 + 5p + 3p + 7q Combine like terms: 17 + 8p + 7q
The cube of the binomial ( (4k - 7q) ) can be calculated using the formula for the cube of a binomial, which is ( (a - b)^3 = a^3 - 3a^2b + 3ab^2 - b^3 ). Here, ( a = 4k ) and ( b = 7q ). Applying the formula, we get: [ (4k - 7q)^3 = (4k)^3 - 3(4k)^2(7q) + 3(4k)(7q)^2 - (7q)^3. ] This simplifies to: [ 64k^3 - 84k^2q + 147kq^2 - 343q^3. ]
the first step in solving the equation is to subtract the nine from the three. you will get negative 6.
It is: 4p^2 -28pq when expanded
This equation is linear, because neither variable symbol occurs to any power except the first.
To simplify the expression (2q + 10 + 7q), combine the like terms. The terms involving (q) are (2q) and (7q), which add up to (9q). Therefore, the simplified expression is (9q + 10).
17p+17q+p-7q-6p = 12p+17q
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