Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc. Also use ^ to indicate powers (eg x-squared = x^2).
Your question has no operator between -7q and 2.
7q+13 = 52 7q = 52-13 7q = 39 q = 39/7
17p+17q+p-7q-6p = 12p+17q
4p+7q
7q = 21 q = 3
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc. And using ^ to indicate powers (eg x-squared = x^2).
7q+13 = 52 7q = 52-13 7q = 39 q = 39/7
Solving by elimination: p = 3 and q = -2
14p + 14q + p - 7q - 6p = 9p + 7q
welll 7xq = 7q..xq would be 7q squared
8 + 5p + 7q + 9 + 3p Reordering: 8 + 9 + 5p + 3p + 7q Combine like terms: 17 + 8p + 7q
It is: 4p^2 -28pq when expanded
the first step in solving the equation is to subtract the nine from the three. you will get negative 6.
This equation is linear, because neither variable symbol occurs to any power except the first.
17p+17q+p-7q-6p = 12p+17q
7q-d4k7l6-pgpzmc-h311fj
5p-7q
4p+7q