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Your question has no operator between -7q and 2.
7q+13 = 52 7q = 52-13 7q = 39 q = 39/7
The cube of the binomial ( (4k - 7q) ) can be calculated using the formula for the cube of a binomial, which is ( (a - b)^3 = a^3 - 3a^2b + 3ab^2 - b^3 ). Here, ( a = 4k ) and ( b = 7q ). Applying the formula, we get: [ (4k - 7q)^3 = (4k)^3 - 3(4k)^2(7q) + 3(4k)(7q)^2 - (7q)^3. ] This simplifies to: [ 64k^3 - 84k^2q + 147kq^2 - 343q^3. ]
To simplify the expression (2q + 10 + 7q), combine the like terms. The terms involving (q) are (2q) and (7q), which add up to (9q). Therefore, the simplified expression is (9q + 10).
17p+17q+p-7q-6p = 12p+17q
7q = 21 q = 3
7q+13 = 52 7q = 52-13 7q = 39 q = 39/7
Solving by elimination: p = 3 and q = -2
14p + 14q + p - 7q - 6p = 9p + 7q
welll 7xq = 7q..xq would be 7q squared
8 + 5p + 7q + 9 + 3p Reordering: 8 + 9 + 5p + 3p + 7q Combine like terms: 17 + 8p + 7q
It is: 4p^2 -28pq when expanded
the first step in solving the equation is to subtract the nine from the three. you will get negative 6.
This equation is linear, because neither variable symbol occurs to any power except the first.
17p+17q+p-7q-6p = 12p+17q
7q-d4k7l6-pgpzmc-h311fj
7q = 21 q = 3
5p-7q