k(k + 5)
2k = 5k-30 Subtract 5k from both sides: -3k = -30 Divide both sides by -3 to find the value of k remembering that a minus divided into a minus becomes a plus: k = 10
That depends what the values of k and b are.
20% = 1/5 = 2/10 = ... = k/(5k), for some constant k. The reciprocal of k/(5k) is (5k)/k = 5/1. Therefore the reciprocal of 20% is 500%.
5000
k(k + 5)
2k = 5k-30 Subtract 5k from both sides: -3k = -30 Divide both sides by -3 to find the value of k remembering that a minus divided into a minus becomes a plus: k = 10
The algebraic expression for "k squared minus 11" is k ² -11. This can't be solved because it's only an expression not an equation.
That depends what the values of k and b are.
K-11
k + 5k = 6k 2 x 3 x k
11 - 5k. If k is a number then substitute it in. Example if k were to equal 2, then 11 - 5*2 = 11-10 = 1. It depends on the value of k.
4k. You can replace "k" and other variables with a familiar object if it helps you to understand why. 5 cookies - a single cookie = 4 cookies, for example.
5k + 2 = -2 Therefore, 5k = -4 k = -4/5 k = -0.8
20% = 1/5 = 2/10 = ... = k/(5k), for some constant k. The reciprocal of k/(5k) is (5k)/k = 5/1. Therefore the reciprocal of 20% is 500%.
35k2 - 22k + 3 = 0 35k2 - 15k - 7k + 3 = 0 5k(7k - 3) - (7k - 3) = 0 (5k - 1)(7k - 3) = 0 5k -1 = 0 or 7k - 3 = 0 5k = 1 or 7k = 3 k = 1/5 or k = 3/7
5000