x-2=3x+1
x=3x+1+2
x-3x=3
-2x=3
x=-3/2
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x2 + 3x + 7 = 5 ∴ x2 + 3x + 2 = 0 ∴ (x + 1)(x + 2) = 0 ∴ x ∈ {-2, -1}
3x-1 = 11 3x = 11+1 3x = 12 x = 4 Therefore: x2+2 = 18
- If 3X - 1 = 11, what is the value of X^2 + X?
x2 + 3x + 3 = 7Subtract 7 from each side:x2 + 3x - 4 = 0Factor the left side:(x + 4) (x - 1) = 0x = - 4x = +1
x2 + 3px + p = 0 x2 + p(3x + 1) = 0 p(3x+1) = -x2 p = -x2/(3x+1) So p can have any value at all. In fact, around x = -1/3, p goes asymptotically to + and - infinity.