x2 + 3x - 7 = 5x + 8; thus, x2 + 3x - 7 - 5x - 8 = x2 - 2x - 15 = (x - 5)(x + 3) = 0. Therefore the solution is x = 5 or -3.
-3/2
X2 + 3X - 18 = 0What two factors of - 18 add up to 3 ??(X - 3)(X + 6)============so, by the zero sum rule,X = 3X = - 6
X2+3x+x+3=x(x+1)+3(x+1)=(x+3)(x+1)
3x-1 = 11 3x = 11+1 = 12 x = 12/3 = 4 Therefore: x2 + 2 = 16 + 2 = 18
x2 plus 3x plus 3 is equals to 0 can be solved by getting the roots.
x2 + 3y = 7 3x + y2 = 3 3y = x2 + 7 y2 = -3x + 3 y = x2/3 + 7/3 y = ± √(-3x + 3) If you draw the graphs of y = x2/3 + 7/3 and y = ± √(-3x + 3) in a graphing calculator, you will see that they don't intersect, so that the system of the given equations has not a solution.
x2 + 3x - 7 = 5x + 8; thus, x2 + 3x - 7 - 5x - 8 = x2 - 2x - 15 = (x - 5)(x + 3) = 0. Therefore the solution is x = 5 or -3.
-3/2
x3 + x2 - 3x - 3 x(x2 + x - 3) - 3
3 - 3x + x2 - x3 = (1 - x)(x2 + 3)
x2 + 3x - 18 = 0 (x - 3)(x + 6) = 0 x = 3 or -6
x^2+3x-18=0 (x+6)(x-3)=0
3(x2 + 3x + 1)
X2 + 3X - 18 = 0What two factors of - 18 add up to 3 ??(X - 3)(X + 6)============so, by the zero sum rule,X = 3X = - 6
x = 5 or x = 6
X2+3x+x+3=x(x+1)+3(x+1)=(x+3)(x+1)