x2 + 3x + 3 = 7
Subtract 7 from each side:
x2 + 3x - 4 = 0
Factor the left side:
(x + 4) (x - 1) = 0
x = - 4
x = +1
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-3/2
X2 + 3X - 18 = 0What two factors of - 18 add up to 3 ??(X - 3)(X + 6)============so, by the zero sum rule,X = 3X = - 6
X2+3x+x+3=x(x+1)+3(x+1)=(x+3)(x+1)
3x-1 = 11 3x = 11+1 = 12 x = 12/3 = 4 Therefore: x2 + 2 = 16 + 2 = 18
x2 + 3px + p = 0 x2 + p(3x + 1) = 0 p(3x+1) = -x2 p = -x2/(3x+1) So p can have any value at all. In fact, around x = -1/3, p goes asymptotically to + and - infinity.