y6 x y2 y4 x y4 y2 x y2 x y4 y2 x y2 x y2 x y2
(x - y)(x + y)
If:xy = x2 + y2 + 2xyThen:x2 + xy + y2 = 0Do you want to solve it for x?x2 + xy + (y/2)2 = (y/2)2 - y2(x + y/2)2 = y2/4 - y2x + y/2 = ± √(-3y2/4)x = -y/2 ± y√(-3) / 2x = (-y ± yi√3) / 2
y2-x2 = (y+x)(y-x)
y2-x-6y+6=0 y2-6y+6=x (y-3)2-3=x so y = 3+sqrt(x+3) or y = 3-sqrt(x+3)
x2-y2=(x-y)(x+y) which is a well known identity.
4 - y2 can be written as 22 - y2. This has become of the form of x2 - y2.Expansion for x2 - y2 is (x+y)(x-y).So, 4 - y2 = 22 - y2 = (2+y)(2-y)
x2 - y2 + 9x - 9y =(x2 + 9x) - (y2 + 9y) =x(x + 9) - y(y + 9)================================Another way to go after it:x2 - y2 + 9x - 9y =(x2 - y2) + 9x - 9y =(x + y) (x - y) + 9 (x - y) =(x + y + 9) (x - y)
y6 x y2 y4 x y4 y2 x y2 x y4 y2 x y2 x y2 x y2
(x - y)(x + y)(x2 - xy + y2)(x2 + xy + y2)
(y-6)(y-4) y x y = y2 y x -4 = -4y y x -6 = -6y -4 x -6 = 24 y2 - 4y - 6y + 24 y2 - 10y + 24
(x - y)(x + y)
0
If:xy = x2 + y2 + 2xyThen:x2 + xy + y2 = 0Do you want to solve it for x?x2 + xy + (y/2)2 = (y/2)2 - y2(x + y/2)2 = y2/4 - y2x + y/2 = ± √(-3y2/4)x = -y/2 ± y√(-3) / 2x = (-y ± yi√3) / 2
y2-x2 = (y+x)(y-x)
X2+y2=25 (x-8)2+y2 =41
2(x - y)(x + y)(x2 - xy + y2)(x2 + xy + y2)