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y6 x y2 y4 x y4 y2 x y2 x y4 y2 x y2 x y2 x y2
(x - y)(x + y)
If:xy = x2 + y2 + 2xyThen:x2 + xy + y2 = 0Do you want to solve it for x?x2 + xy + (y/2)2 = (y/2)2 - y2(x + y/2)2 = y2/4 - y2x + y/2 = ± √(-3y2/4)x = -y/2 ± y√(-3) / 2x = (-y ± yi√3) / 2
y2-x2 = (y+x)(y-x)
y2-x-6y+6=0 y2-6y+6=x (y-3)2-3=x so y = 3+sqrt(x+3) or y = 3-sqrt(x+3)