This type of expression is what we call a "difference of squares". This occurs whenever a perfect square is subtracted from another perfect square. It can be factored out to:
(x + y)(x - y)
To see why that is, try multiplying those two factors back together:
(x + y)(x - y)
= x(x - y) + y(x - y)
= x2 - xy + yx - y2
= x2 - xy + xy - y2
= x2 - y2
The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.
It's m = y2 - y1/ x2- x1 It's m equals y2 minus y1 over x2 minus x1
X2 + y2 = 100 = r2 r = 10
-2
Proper form first. X2 + Y2 = 1 Y2 = 1 - X2 Y = (+/-) sqrt(1 - X2) -------------------------- zero out the X Y = (+/-) sqrt(1 - 02) Y = 1 ----------------the radius of this circle
(x - y)(x + y)(x2 - xy + y2)(x2 + xy + y2)
x2 -y2 +4y-4=(x+y)(x-y)+4y-4
x2-y2=(x-y)(x+y) which is a well known identity.
(x - y)(x + y)
4 - y2 can be written as 22 - y2. This has become of the form of x2 - y2.Expansion for x2 - y2 is (x+y)(x-y).So, 4 - y2 = 22 - y2 = (2+y)(2-y)
(x2 - xy + y2)(x + y)
There is no expansion for x2 + y2
What do you want to convert it to? x2 + y2 = 2x If you want to solve for y: x2 + y2 = 2x ∴ y2 = 2x - x2 ∴ y = (2x - x2)1/2 If you want to solve for x: x2 + y2 = 2x ∴ x2 - 2x = -y2 ∴ x2 - 2x + 1 = 1 - y2 ∴ (x - 1)2 = 1 - y2 ∴ x - 1 = ±(1 - y2)1/2 ∴ x = 1 ± (1 - y2)1/2
(x + y)(x - y) = 16
-x2(y - 2)(y + 2)(y2 + 4)
The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.
Line (x1, y1, x2, y1); Line (x2, y1, x2, y2); Line (x2, y2, x1, y2); Line (x1, y2, x1, y1);