40 square units
If you have the area then you can find the width by dividing the area by the length...having the length by itself is broad
Area= length * width length= width + 5 so.... Area= width * (width + 5) Area= width^2 + 5width (going to use w for width.) 66= w^2 + 5w w^2 + 5w - 66= 0 Now factor! (w - 6)(w + 11) Solve for w, and since area can't be negative, you get.. w=6 length= 6+5= 11
width 1, length 10 width 2, length 5
The area of a rectangle is length times width. If length and width are in inches, the area will be square inches.
Since all sides of the square are the same length, if the length is 5, the width is five. Therefore area= length x width = 5 x 5 = 25. The answer is 25 square feet.
As an example: 4 x 5 = 20, when doubled only once, it is 8 x 10 = 80
length times width
If you have the area then you can find the width by dividing the area by the length...having the length by itself is broad
Area= length * width length= width + 5 so.... Area= width * (width + 5) Area= width^2 + 5width (going to use w for width.) 66= w^2 + 5w w^2 + 5w - 66= 0 Now factor! (w - 6)(w + 11) Solve for w, and since area can't be negative, you get.. w=6 length= 6+5= 11
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle
length x width= area ex if the length of the square was 10 and the width was 5, 10 x 5= 50units^2
Area = Length * Width = 5 m * 3 m = 15 square metres
width 1, length 10 width 2, length 5
The area of a rectangle is length times width. If length and width are in inches, the area will be square inches.
Since all sides of the square are the same length, if the length is 5, the width is five. Therefore area= length x width = 5 x 5 = 25. The answer is 25 square feet.
This is a rectangle with length 5 units and width 3 units. The area = length x width = 5 x 3 = 15 sq units. The perimeter = 2 x (length + width) = 2 x 8 = 16 units.
It is: 10 times 5 = 50 square in