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the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle

Q: The length of a rectangle is 5 more then the width Find the perimeter and the area of the rectangle?

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The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.

Length of rectangle is 5 inches and its width is 4 inches Check: 2*(5+4) = 18 inches which is its perimeter

98 square feet

width=15 length=35

The perimeter of a rectangle is total length of all 4 sides = 2 x length + 2 x width. The semiperimeter is therefore half this amount = length + width.

Related questions

The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.

If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.

you need length and width length multiply width = area length + length + width + width = perimeter

Length + length + width + width = perimeter. Length + width x 2 = perimeter

perimeter = 2 x (length + width) ⇒ length + width = perimeter ÷ 2 ⇒ length = (perimeter ÷ 2) - width So to find the length of the given rectangle, subtract the width from half the perimeter is how to do it. IF you meant "What is the length..." then: length = perimeter ÷ 2 - width = 40 ÷ 2 - 2 in = 20 - 2 in = 18 in

Perimeter = 2 * width + 2 * length, so rearranging --> width = (Perimeter / 2) - length

You divide the perimeter by the width and you get the lenght

Length = (Perimeter - twice width) / 2

length 18 width 7

by appying 2l+2w

Perimeter = 2*(L + W).

a rectangle has a perimeter of 72m. If the length is 20 m longer than the width find its dimensions?