Assuming this question is asking about a rectangle:
Perimeter = 2l + 2w and according to this problem Perimeter = 96, so
96 = 2l + 2w
If l = 5w, then we can replace each l in the statement above with 5w, so
96 = 2(5w) + 2w
96 = 10w + 2w
96 = 12w
8 = w
If 8 = w, and l = 5w, then l = 5 times 8 = 40
The area of a rectangle is length (l) times width (w), so
A = lw
A = (40) (8)
A = 320 square units
48 times 96 equals 4,608.
The perimeter of the square is 96.
8 by 12
Any number less than 576 cm2. A square, with sides of 24 cm will have a perimeter of 96 cm and an area of 576 cm2. Suppose the sides of the rectangle are 24+x cm and 24-x cm, where 0<x<24. Then the perimeter will be 96 cm while the area will be (24+x)*(24-x) = 576 - x2 cm2 The area can have any value in the range (0, 576) depending on the value of x.
Area = 3*45 = 135 square feet. Perimeter = 2*(3 + 45) = 2*48 = 96 feet.
96 feet.
What are the dimensions of a rectangle that has a perimeter of 56 units and an area of 96 square units
48 times 96 equals 4,608.
4X24
The perimeter of the square is 96.
4 x 24
4 x 24
8 by 12
Any number less than 576 cm2. A square, with sides of 24 cm will have a perimeter of 96 cm and an area of 576 cm2. Suppose the sides of the rectangle are 24+x cm and 24-x cm, where 0<x<24. Then the perimeter will be 96 cm while the area will be (24+x)*(24-x) = 576 - x2 cm2 The area can have any value in the range (0, 576) depending on the value of x.
Area = 3*45 = 135 square feet. Perimeter = 2*(3 + 45) = 2*48 = 96 feet.
The area is 96*sqrt(3) = 166.3 sq inches, approx.
Assuming 96 refers to the area of therectangle, the answer is: infinite. Consider the following sequence of rectangles with breadh B units and length L units.: Breadth = 1 Length = 96. Area = 96, Perimeter = 194 B= 0.1, L = 960. A = 96, P = 1920.2 B = 0.01, L =9600. A = 96, P = 19200.02 B = 0.001, L = 96000. A = 96, P = 192000.002 There is no limit to how small B can get and therefore, how large P can get.