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Yard is a measure of length; there is no standard conversion to area. Different figures of the same length, or of the same perimeter, can have different areas.

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Q: What is the area of 2 yds?
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The volume of a pyramid is Area of the base Height one third What is the volume of a pyramid where its base is 2 yds by 2 yds and height is 6 yds?

8


What are the rectangle sides of a 47 acre plot?

Any you like as long as the length of the plot in yards is 227,480 yds divided by the width, making the AREA of the rectangle always 47 acres (227,480 sq yds) eg the rectangle could be: 1 yd by 227,480 yds; 2 yds by 113,740 yds; 22 yds by 10,340 yds 220 yds by 1,034 yds (or 1 furlong by 47 chains) An acre was originally the area that an ox could plough in a day, and is likely to have been an rectangle a chain wide and a furlong (furrow-long) long, ie 22 yds by 220 yds = 4840 sq yds. However, as it is a measure of area, it doesn't matter what shape it is as long as the enclosed area covers 1 acre, for example it could be a circle with a radius of approx 39.25 yds


What is the perimeter of a rectangle that is 5yds in length and 3yds in width?

Perimeter = 2*(5 yds + 3 yds) = 2*8 yds = 16 yds


What is the perimeter of a 1.5 acre circle?

Area = π × radius² → radius = √(Area / π) Circumference = 2 × π × radius = 2 × π × √(Area / π) = 2 × √(Area × π) 1 acre = 4840 sq yds → circumference = 2 × √(1.5 × 4840 sq yds × π) ≈ 302 yds.


What is the surface area of a pyramid if the base is 6 yards by 6 yards and the height is 4 yards?

If the height of each side of the pyramid is 4 yards, then you have to figure out each of the four sides and add them to the base. Luckily, this is easy. The base: l x w = 6 yds x 6 yds = 36 sq. yds. The sides: 1/2 x l x w = 1/2 x 6 yds x 4 yds = 12 sq. yds There are four sides, so 12 sq. yds. x 4 = 36 sq. yds. Add the base, and 36 sq. yds. + 12 sq. yds. = 48 sq. yds. That's your answer!