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Area = length x width, so length = area/width = 116/4 = 29 yds

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29 yards

Q: What is the length of a rectangle if the area is 116 sq yds and the width is 4 yds?

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50

It is: 841 square mm

Double of 58 is 116.

All multiples of 116 are divisible by 116. There is an infinite number of multiples of 116.

116 x 1 = 116 58 x 2 = 116 29 x 4 = 116

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There are many possibilities with out knowing its width, length or any other useful information.

Do-it-in-your-head method: 1. Length + width is half the perimeter ie 116 in 2. 116 minus 68 is 48, half of 48 is 24 which is the width, making the length 92 in

The perimeter can be written as 2x + 2y = P where the x is length and y is width we know that y = x + 58 so 2y = 2x + 116 2x + 2x + 116 = 260 4x=148 x=37 37+58=95 y=95

50

645 sq cm.

116

The distance around or Perimeter of a Rectangle is equal to the sum of the length of the 4 sides.18' + 40' + 18' + 40' = 116'

Any length equal to or greater than 4308.132 metres. 116 hectares = 1 160 000 metres2 This area can be contained in any rectangle such that L*W = 1 160 000 m2 where L and W are its length and width. L and W cannot be smaller than sqrt(1160000) m = 1077.033 m when the perimeter would be 4*1077.033 m = 4308.132 m But you can increase the length to 1160m (W = 1000m) and perimeter = 4320 m or double L to 2320 m, W = 500 m and P = 5640 m or double L again to 4640 m, W = 250 m and P = 9780 m When L = 1 160 000 m and W = 1 m, P = 2 320 002 m But you can continue increasing L forever.

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