Just do 3 times 13 which is 39.Then 39 times 7 ; that gives the answer ...... square feet. You do the sum, fill in the dots above, ok?
16 yd., 3 ft.
It is: 7 times 3 = 21 square feet
7 ft 3 inches = 221 cm
No, you cannot completely cover a 3 ft by 6 ft area with 3 ft by 3 ft tiles. The area of the tiles is 9 square feet, while the area to be covered is 18 square feet. Since the tiles cannot be cut or partially used to fill the remaining space, you would be left with an uncovered area of 3 ft by 3 ft.
16 2/3 x 13 = 216 2/3 sqft
1 yd = 3 ft area = ½ × (sum bases) × height → area = ½ × (5 ft + 3½ yd) × 7 ft = ½ × (5 ft + (3½ × 3) ft) × 7 ft = ½ × (5 + 10½ ft) × 7 ft = 54¼ sq ft
16 yd., 3 ft.
It is: 7 times 3 = 21 square feet
7 ft 3 inches = 221 cm
3 feet in 1 yard, so which is greater 6 ft or 7 ft.
No
1 ft = (1/3) yd 1 in = (1/12) ft = (1/36) yd So 1yd 7ft 14in = 1 + (7/3) + (14/36) yd = (36/36) + (84/36) + (14/36) yd = (134/36) yd. (134/36) = 3.7222 yd (rounded)
Convert to same units and compare: 1 yd = 3 ft → 4 yd = 4 x 3 ft = 12 ft < 13 ft → 13 ft is more than 4 yards.
16 2/3 x 13 = 216 2/3 sqft
One cubic yard is 3 ft x 3 ft x 3ft (e.g. 27 cubic feet). 8ft x 7ft = 56sqft 56sqft x 2ft = 112cuft 112 / 27 = 4.148 So 8ft x 7ft x 2ft = 4.148 cubic yards
yes. and you only need 2 of them.
18 cu. ft