1 yd = 3 ft
area = ½ × (sum bases) × height
→ area = ½ × (5 ft + 3½ yd) × 7 ft
= ½ × (5 ft + (3½ × 3) ft) × 7 ft
= ½ × (5 + 10½ ft) × 7 ft
= 54¼ sq ft
It is probably 54.25 square feet.
Anything from just over zero to infinity; with the height being 32/base cm.
A triangular prism has five bases because it can be flipped over to form five different bases
vertical height over lengh
It depends on left over after what!
The distributive law of multiplication over addition says that if x, y and z are any numbers, then x(y+z) = xy + xz . It's true not only for integers, but also for real numbers or even complex numbers. Here's a proof / graphical explanation: __________ |*****|***| ^ |*****|***| | |*****|***| |x |*****|***| | |*****|***| v --------------- <--y--><-z-> Consider the ASCII rectangle above. It has height x and width y+z, therefore its area is x(y+z). Alternatively, it can be viewed as two smaller rectangles joined together. The one on the left has height x and width y, so its area is xy. Similarly, the one on the right has area xz. So the total area is xy + xz. Therefore x(y+z) = xy + xz.
Suppose you have a trapezium whose parallel sides (bases) are of lengths A and B units, and where the height is h units If you flip a trapezium over and append it to the original along one of the bases you will have a parallelogram whose base is A+B units in length and whose height is h units. So 2*Area of trapezium = Area of parallelogram = (A + B)*h
Suppose you have a trapezium whose parallel sides (bases) are of lengths A and B units, and where the height is h units If you flip a trapezium over and append it to the original along one of the bases you will have a parallelogram whose base is A+B units in length and whose height is h units. So 2*Area of trapezium = Area of parallelogram = (A + B)*h
A trapezoid is a two-dimensional shape, so it doesn't have surface area. The AREA of a trapezoid is: (Base1+Base2) X Height Divided/Over 2. For example: Imagine a trapezoid. Base 1 (top) measures 6 and Base 2 (bottom) measures 8. The height of the trapezoid from B1 to B2 is ''3''. Procedure: (6+8)x3 Divided by 2 14x3 Divided by 2 42 Divided by 2 Ans: 21^2
Anything from just over zero to infinity; with the height being 32/base cm.
4 × 6 meters in the area and just over 3 meters in height
No because the 4 interior angles of a trapezoid add up to 360 degrees and 4 obtuse angles would be over 360 degrees
1/2bh or bh over 2Half of the base times the heightorBase times height divided by two
The speed of the wind, gravitational pull of the moon interactions with other waves time duration the wind has blown over a given area width of area affected by fetch water depth. These are some of the reasons that affect the height of ocean waves.
Bases of buildings and dams are spread over a large area. Hence, the pressure exerted by the building on the earth's surface is less. thus reducing the risk of sinking.
the area between the bases and home plate is called the base path.
Looking at the height of the wall, it was improbable that he would be able to climb over it.Looking at the height of the wall, it was improbable that he would be able to climb over it.Looking at the height of the wall, it was improbable that he would be able to climb over it.Looking at the height of the wall, it was improbable that he would be able to climb over it.Looking at the height of the wall, it was improbable that he would be able to climb over it.Looking at the height of the wall, it was improbable that he would be able to climb over it.Looking at the height of the wall, it was improbable that he would be able to climb over it.Looking at the height of the wall, it was improbable that he would be able to climb over it.Looking at the height of the wall, it was improbable that he would be able to climb over it.Looking at the height of the wall, it was improbable that he would be able to climb over it.Looking at the height of the wall, it was improbable that he would be able to climb over it.
Perimeter P= a+b+c+d Area A= base times height over 2 times h