4m+15=8m-5 or,4m=20 or,m=5
4m
2(4m - 3)
24
To determine if the lengths 8m, 4m, and 2m can form a right triangle, we can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides. Here, the longest side is 8m. Calculating, we find that (8^2 = 64) and (4^2 + 2^2 = 16 + 4 = 20), which does not equal 64. Therefore, 8m, 4m, and 2m cannot form a right triangle.
4m+15=8m-5 or,4m=20 or,m=5
4m
It is 50%.
2(4m - 3)
96m3
Rectangles are really simple. The perimeter is twice the length plus twice the width (in this case 4m x 2 = 8m, 5m x 2 = 10m, and 8m + 10m = 18m). The area is simply the length times the width (in this case, 4m x 5m = 20m2).
224 m to the 3rd power
2(4m-3)
8m-7<4m+5
The area of 4m by 4m is 16 square meters.
24
It appears to be a scalene triangle from the given dimensions.