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4m
first, multiply the base and height then divide it into 2 example: base:4m height:2m multiply 4 by 2= 8 then divide 8 by 2= 4 4m squared
6m + 5n - 4m + 7n = 2m + 12n
2m + 13n
2m(5k - 4m)(25k2 + 20km + 16m2)
It is: 2m times 2m is equivalent to 4m^2
The triangle with side lengths of 2m, 4m, and 7m does not form a valid triangle. In a triangle, the sum of the lengths of any two sides must be greater than the length of the third side according to the Triangle Inequality Theorem. In this case, 2m + 4m is less than 7m, violating the theorem. Therefore, a triangle with these side lengths cannot exist in Euclidean geometry.
4m
Well, darling, if the length of your rectangle is 4m and the width is 2m, then the perimeter is simply calculated by adding up all the sides, which gives you 4m + 4m + 2m + 2m, totaling 12 meters. Voilà, there's your answer!
6m + 7 - 2m + 1 = 4m + 8 If you meant: (6m + 7) - (2m + 1) = 4m + 6
40m^3
first, multiply the base and height then divide it into 2 example: base:4m height:2m multiply 4 by 2= 8 then divide 8 by 2= 4 4m squared
40 cubic meters
6m + 5n - 4m + 7n = 2m + 12n
None. By definition a hole is an empty space.
2m + 13n
The perimeter of a triangle is the sum of its three sides. If two are 3m and 2m then their sum is 3m + 2m = 5m And the remaining side can be calculated by taking this sum from the perimeter → the other side is 9m - 5m = 4m long.