20 sq. m
The lengths of the sides of a quadrilateral are not enough to determine its area since the shape is not rigid: it can be flexed.
5m*8m = 40m/2=20 20 is your answer
Area: A = pi x r2 A = 3.14 x (8m)2 A = 200.96m2 Circumference: C = 2 x pi x r C = 2 x 3.14 x 8m C = 50.24m
.230
40m
8m*5m=40 m2 The area of the rectangle is 40m2
8m x 5m x 1.5m = 60m3 = 60*1000 litres ie 60 kilolitres.
5m−3+8m =5m+−3+8m Combine Like Terms: =5m+−3+8m =(5m+8m)+(−3) =13m+(−3)
Rectangles are really simple. The perimeter is twice the length plus twice the width (in this case 4m x 2 = 8m, 5m x 2 = 10m, and 8m + 10m = 18m). The area is simply the length times the width (in this case, 4m x 5m = 20m2).
20 sq. m
To find the area of a quadrilateral with sides of 7m, 4m, 5m, and 3m, you can use Brahmagupta's formula for the area of a cyclic quadrilateral: Area = √(s-a)(s-b)(s-c)(s-d), where s is the semiperimeter (s = (a + b + c + d) / 2) and a, b, c, and d are the lengths of the sides. Plug in the values of the sides into the formula to calculate the area.
8m + 3n - 5m + 10n = 3m +13n
you do 9m x 5m =45m to easy
The lengths of the sides of a quadrilateral are not enough to determine its area since the shape is not rigid: it can be flexed.
9m x 5m = 45 m2
5m*8m = 40m/2=20 20 is your answer