The lengths of the sides of a quadrilateral are not enough to determine its area since the shape is not rigid: it can be flexed.
17
A right triangle with a hypotenuse of 10m and a base of 5m has an area of: 21.65m2
15m + 4n - 5m + 9n = 10m + 13n
The given terms = 10m+2
5m2 - 17m + 12 = 0∴ 5m2 - 5m - 12m + 12 = 0∴ 5m(m - 1) - 12(m - 1) = 0∴ (5m - 12)(m - 1) = 0∴ m ∈ {1, 12/5}
17
A right triangle with a hypotenuse of 10m and a base of 5m has an area of: 21.65m2
Could be a 10m x 10m square, could be a 20m x 5m rectangle etc
5m-5n+5m+5n When simplified: 10m
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150
3m Springboard is 3m 5m springboard is 5m 10m Platform is 10m
Rectangles are really simple. The perimeter is twice the length plus twice the width (in this case 4m x 2 = 8m, 5m x 2 = 10m, and 8m + 10m = 18m). The area is simply the length times the width (in this case, 4m x 5m = 20m2).
15m + 4n - 5m + 9n = 10m + 13n
Gather the m's and n's by rewriting it. 7m - 11n - n + 5m 7m + 5m -11n - n (7m + 5m) + (-11n - n) 12m - 12n ■
If you have lifted the object 5m off the ground, you would have pulled 10m of rope through the pulley system. This is because as the object gets lifted, the rope length on both sides of the pulley decreases by the same amount.
The given terms = 10m+2