Area = 0.5*base*height 18 = 0.5*4*H So H = 9 feet
if the bases are b1 and b2, then: area = ½ × (b1 + b2) × h → 2 × area ÷ h = b1 + b2 → b2 = 2 × area ÷ h - b1 = 2 × 156.6 m² ÷ 18 m - 6 m = 11.4 m
Yes b x h = 36 b = h = 6 = sqaure b = 9 and h = 4 = rectangle b = 18 and h = 2 = rectangle, etc.
34 times.
a=1/2bh b=h=6 a=.5*6*6 a=18
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Area = 0.5*base*height 18 = 0.5*4*H So H = 9 feet
45-h equals 38 = 7
if the bases are b1 and b2, then: area = ½ × (b1 + b2) × h → 2 × area ÷ h = b1 + b2 → b2 = 2 × area ÷ h - b1 = 2 × 156.6 m² ÷ 18 m - 6 m = 11.4 m
Galena, Kansas to Clearwater, Florida is 18 h 34 min (1,222.1 mi) via I-75 South.
H. H. Holmes died on May 7, 1896 at the age of 34.
18 H in a GC? Well, darling, that's 18 holes in a golf course. So, grab your clubs, hit the green, and try not to throw a tantrum when you miss that crucial putt. Remember, it's just a game... or is it?
Yes b x h = 36 b = h = 6 = sqaure b = 9 and h = 4 = rectangle b = 18 and h = 2 = rectangle, etc.
Area A = 1/2 base b time height h b = 2A/h = 270/15 = 18 inches
H
Yes it is.
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