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It's a right triangle, so its 80*18/2= 80*9= 720

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Q: What is the area of a 18 by 80 by 82 triangle?
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What is 18 percent of 82?

18% of 82 = 18% * 82 = 0.18 * 82 = 14.76


What is 80 over 82 simplified?

80/82 = 40/41


Find the tan of the base angle of an isosceles triangle if the equal sides are 82cm long and the other side is 36cm long?

An isosceles triangle can be considered as being two right angled triangles joined together and if we divide the base by 2 this gives us two adjacent sides of 18cm. By rearranging Pythagoras' Theorem we can calculate that the opposite side or perpendicular height of the triangle is 80cm: Pythagoras' Theorem: 822-182 = 6400. The square root 6400 is 80. Tangent = opposite/adjacent 77.31961651o = 80/18 Alternatively the Cosine ratio can be used: Cosine = adjacent/hypotenuse 77.31961651o = 18/82 Or even the Sine ratio: Sine = opposite/hypotenuse 77.31951616o = 80/82 Therefore the isosceles triangle has two equal base angles of 77.32 degrees correct to two decimal places.


What is 82 minus 18?

82 - 18 = 64


What is 82 rounded to the nearest 10?

80

Related questions

What is thr length of the hypotenuse of a right triangle with legs 18 and 80?

Square root of (18*18+80*80) sqr(324+6400) sqr(6724) 82


What is the length of in the right triangle below with legs of 18 and 80?

Using Pythagoras' theorem for a right angle triangle its hypotenuse is 82 units in length


What is 18 percent of 82?

18% of 82 = 18% * 82 = 0.18 * 82 = 14.76


What is 80 over 82 simplified?

80/82 = 40/41


Find the tan of the base angle of an isosceles triangle if the equal sides are 82cm long and the other side is 36cm long?

An isosceles triangle can be considered as being two right angled triangles joined together and if we divide the base by 2 this gives us two adjacent sides of 18cm. By rearranging Pythagoras' Theorem we can calculate that the opposite side or perpendicular height of the triangle is 80cm: Pythagoras' Theorem: 822-182 = 6400. The square root 6400 is 80. Tangent = opposite/adjacent 77.31961651o = 80/18 Alternatively the Cosine ratio can be used: Cosine = adjacent/hypotenuse 77.31961651o = 18/82 Or even the Sine ratio: Sine = opposite/hypotenuse 77.31951616o = 80/82 Therefore the isosceles triangle has two equal base angles of 77.32 degrees correct to two decimal places.


What is 82 minus 18?

82 - 18 = 64


What is 100-18?

100-18 = 82


What is 82 rounded to the nearest 10?

80


What is the interquartile range in these numbers 93 92 89 85 82 80 77 74 71 63?

It is 18.


What is 82 to the nearest tens?

82 to the nearest tens = 80


What is the sum of 80 and 2?

It is: 80+2 = 82


What is 82 round to the nearest ten?

80