18% of 82 = 18% * 82 = 0.18 * 82 = 14.76
80/82 = 40/41
An isosceles triangle can be considered as being two right angled triangles joined together and if we divide the base by 2 this gives us two adjacent sides of 18cm. By rearranging Pythagoras' Theorem we can calculate that the opposite side or perpendicular height of the triangle is 80cm: Pythagoras' Theorem: 822-182 = 6400. The square root 6400 is 80. Tangent = opposite/adjacent 77.31961651o = 80/18 Alternatively the Cosine ratio can be used: Cosine = adjacent/hypotenuse 77.31961651o = 18/82 Or even the Sine ratio: Sine = opposite/hypotenuse 77.31951616o = 80/82 Therefore the isosceles triangle has two equal base angles of 77.32 degrees correct to two decimal places.
82 - 18 = 64
80
Square root of (18*18+80*80) sqr(324+6400) sqr(6724) 82
Using Pythagoras' theorem for a right angle triangle its hypotenuse is 82 units in length
18% of 82 = 18% * 82 = 0.18 * 82 = 14.76
80/82 = 40/41
An isosceles triangle can be considered as being two right angled triangles joined together and if we divide the base by 2 this gives us two adjacent sides of 18cm. By rearranging Pythagoras' Theorem we can calculate that the opposite side or perpendicular height of the triangle is 80cm: Pythagoras' Theorem: 822-182 = 6400. The square root 6400 is 80. Tangent = opposite/adjacent 77.31961651o = 80/18 Alternatively the Cosine ratio can be used: Cosine = adjacent/hypotenuse 77.31961651o = 18/82 Or even the Sine ratio: Sine = opposite/hypotenuse 77.31951616o = 80/82 Therefore the isosceles triangle has two equal base angles of 77.32 degrees correct to two decimal places.
100-18 = 82
82 - 18 = 64
80
It is 18.
82 to the nearest tens = 80
It is: 80+2 = 82
80