Chat with our AI personalities
Well because 8¢ is less than 16¢, it would be the 8 inch pizza...Now if you are wondering which one is better value, the 16" pizza has 4 times the area of the 8" pizza, but is only 2 times the cost, so obviously the 16" pizza is a better bang for the buck, so to speak.
Is the 8 inches of the pizza the diameter or circumference? Is the 8-inches of the box the area of side length? If the diameter if the pizza and the side length of the box are both 8-inches, then the pizza will barely fit. If the circumference of the pizza is 8 inches, that means that the diameter is 8/pi = 2.546..... and that would fit in a box with side lengths of 8-inches. If the box's area is 8-inches, that means the side lengths are the square root of 8=2.828.... A pizza of diameter 8-inches won't fit, but a pizza of circumference of 8-inches will.
To find the area of each slice of a 12-inch pizza, first calculate the area of the entire pizza using the formula ( A = \pi r^2 ). The radius is 6 inches (half of the diameter), so the area is approximately ( A = \pi (6)^2 \approx 113.1 ) square inches. Since the pizza is cut into 8 equal slices, the area of each slice is about ( \frac{113.1}{8} \approx 14.14 ) square inches. Rounding to the nearest square inch, each slice has an area of approximately 14 square inches.
Find the areas, then the area/dollar. Area = pir2 Area of 12 incher = 3.1416 X 62 = 113 sq. inches 10.95/113 = 0.097 dollars/sq. inch Area of 8 incher = 3.1416 X 42 = 50 sq. inches 7.49/50 = 0.15 dollars/sq. inch So the 12 inch round gives more for your money at about 10 cents per sq. inch versus about 15 cents per sq. inch for the 8 incher.
The area of the pizza inceases as the square of the radius (or diameter). Assuming the thickness remains the same, then the volume also increases as the square of the radius. So, double radius implies quadruple area implies quadruple cost.