Well because 8¢ is less than 16¢, it would be the 8 inch pizza...Now if you are wondering which one is better value, the 16" pizza has 4 times the area of the 8" pizza, but is only 2 times the cost, so obviously the 16" pizza is a better bang for the buck, so to speak.
Is the 8 inches of the pizza the diameter or circumference? Is the 8-inches of the box the area of side length? If the diameter if the pizza and the side length of the box are both 8-inches, then the pizza will barely fit. If the circumference of the pizza is 8 inches, that means that the diameter is 8/pi = 2.546..... and that would fit in a box with side lengths of 8-inches. If the box's area is 8-inches, that means the side lengths are the square root of 8=2.828.... A pizza of diameter 8-inches won't fit, but a pizza of circumference of 8-inches will.
Find the areas, then the area/dollar. Area = pir2 Area of 12 incher = 3.1416 X 62 = 113 sq. inches 10.95/113 = 0.097 dollars/sq. inch Area of 8 incher = 3.1416 X 42 = 50 sq. inches 7.49/50 = 0.15 dollars/sq. inch So the 12 inch round gives more for your money at about 10 cents per sq. inch versus about 15 cents per sq. inch for the 8 incher.
The area of the pizza inceases as the square of the radius (or diameter). Assuming the thickness remains the same, then the volume also increases as the square of the radius. So, double radius implies quadruple area implies quadruple cost.
The area of a 16" pizza is 201.2 sq inches which is 0.1297 sq metres
Well because 8¢ is less than 16¢, it would be the 8 inch pizza...Now if you are wondering which one is better value, the 16" pizza has 4 times the area of the 8" pizza, but is only 2 times the cost, so obviously the 16" pizza is a better bang for the buck, so to speak.
Area of a 14 inch pizza = 43.98in2. Area of a 12 inch pizza = 37.70in2. Difference between the two = 6.28in2.
Is the 8 inches of the pizza the diameter or circumference? Is the 8-inches of the box the area of side length? If the diameter if the pizza and the side length of the box are both 8-inches, then the pizza will barely fit. If the circumference of the pizza is 8 inches, that means that the diameter is 8/pi = 2.546..... and that would fit in a box with side lengths of 8-inches. If the box's area is 8-inches, that means the side lengths are the square root of 8=2.828.... A pizza of diameter 8-inches won't fit, but a pizza of circumference of 8-inches will.
Assume both pizzas are cut into eight slices. 3 slices of the 12 inch pizza make an angle of3 pi/4 and area is 1/2 radius squared times angle where radius is 6 inch so area = 42.4 sq in 2 slices of the 16 inch pizza make an angle of pi/2 and area is 1/2 radius squared times angle where radius is 8 inch so area = 50.2 sq in so the two 16 inch slices give you more pizza
1 12 inch pizza for 9.99 is the better deal. Whether or not we consider the total volume of pizza purchased or just the surface area of pizza (which reflects how much topping there will be) the proportion between the 12 inch and the two 8 inch pizzas (combined) always results in 9:8. So you are getting slightly more pizza with the 12 inch pizza, and it is cheaper, so it is the better deal. Volume = pi * r2 * h. As r2 for the 12 inch pizza = 62 = 36, this is more than 2 * 42 = 32 by the proportion 36:32, which simplifies to 9:8.
(3.141*5)^2
8
Based on same ingredients and amounts I would say an 8" for $7 is better. The costs per inch of pizza is less than that of a 12".
225 square inches
The 18" refers to the width (diameter) of the pizza.
Find the areas, then the area/dollar. Area = pir2 Area of 12 incher = 3.1416 X 62 = 113 sq. inches 10.95/113 = 0.097 dollars/sq. inch Area of 8 incher = 3.1416 X 42 = 50 sq. inches 7.49/50 = 0.15 dollars/sq. inch So the 12 inch round gives more for your money at about 10 cents per sq. inch versus about 15 cents per sq. inch for the 8 incher.
If they are the diameters of the pizzas then:- Each slice of the 7 inch pizza is about 9.62 square inches Each slice of the 9 inch pizza is about 7.95 square inches