It is not possible to answer the question without information about the shape.
The fact that there are three numbers given might suggest that it is a triangle. However the three lengths are not consistent with a triangle.
-- Add the lengths of the two 'bases' (the two parallel sides). -- Multiply the sum by the height of the trapezoid. -- Take 1/2 of the product. That's the trapezoid's area.
area of a square- 2S = side times side so, in this case 10 times 10 = 100 so the answer is 100unit^2 (100unit square)
20 / 2 = 10So 10 lengths can be cut from 20 metres.ten20 / 2 = 10
That depends on the geometric figure.
Area = 1/2 (sum of bases) times height Area = (8+12)/2 x 4 Area = 10 x 4 = 40
It is the sum of the areas of all the components.
-- Add the lengths of the two 'bases' (the two parallel sides). -- Multiply the sum by the height of the trapezoid. -- Take 1/2 of the product. That's the trapezoid's area.
area of a square- 2S = side times side so, in this case 10 times 10 = 100 so the answer is 100unit^2 (100unit square)
Unless there is a given measurement of the lengths of the sides of the figure (ex. cm., mm., in.) you would say units, and put a little 2 as an exponent because you need to write square units.
Area of the trapezoid: 0.5*(8+11)*10 = 95 square measurements
20 / 2 = 10So 10 lengths can be cut from 20 metres.ten20 / 2 = 10
That depends on the geometric figure.
Area = 1/2 (sum of bases) times height Area = (8+12)/2 x 4 Area = 10 x 4 = 40
A cube cannot have different side lengths.
figure 1 is a5 centimeter squre. from 2-cenimeter, squrare are rwevmoed from each of the four coners of figure 1. what is the area of the remainder of figure 1as shown in figure 2
This is a nth term question. The formula for this is: n³ + 2 So, replace the n with 10: 10³ +2 = 1002
It is the area of the 2-D figure.