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42 = 4 x 4 = 16 cm2

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Q: What is the area of a square whose side is 4cm?
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Related questions

The area of a square of length 4cm?

A square with a side length of 4cm has an area of 16cm2


Is it possible that a square can have the same perimeter and area?

Yes (apart from units):If the side of a square is 4cm then itsperimeter is 4cm + 4cm + 4cm + 4cm = 4 x 4cm = 16cm;area is 4cm x 4cm = 16cm2


What is the length of a square with and area 4cm?

Each side is 2cm


What is the area of a square that's 2 centimeters on each side?

4cm


What is the area a of a square with sides 2cm long?

A square with a side length of 2cm has an area of 4cm2


What is the area of a 4 by 4 square?

if you mean 4cm by 4cm square, then the area is 16cm2


Find the area and perimeter of the square with side of 4cm?

Area = (side)2 = 16 square centimeters Perimeter = 4 x side = 16 centimeters


Find the length of a side of a square whose diagonal is 4cm?

a≈2.83cm The sides are the square root of 8 cm, approximately 2.8284 cm


What is the equation for the area is the length of a side squared?

to work out the area of a sqaure it is the length of the side multiplied by another side. seing as the sides of a sqaure are all equal, is is the side of a square multiplied by itself. for example if the side of a square was 4cm the equation would be: 4cm x 4cm = 16cm^2 do not get this equation confused with the equation for a rectangle which is length multiplied by the width. (L x W)


What is the area of a right triangle 3cm by 4cm?

For it to be a right angle triangle the 3rd side must be 5cm


What is the surface area of a cone whose base radius is 4CM and has a slant height of 6CM?

Surface area = pi*4*6 = 75.398 square cm


If the area of the square is 16cm what is the length of each side?

Well, darling, if the area of the square is 16cm, then the length of each side is the square root of 16, which equals 4cm. It's simple math, honey, no need to overcomplicate things. So, grab a ruler and measure those sides, you'll see I'm right on the money.