Perimetre of squre is 4*(side) and side is 8 cm so perimetre is 4*8=32cm
You are asking what the perimeter of a figure is when you already know it. What kind of question is that? I'll assume you mean the area of the square is 64 cm2. The area of a square in calculated by multiplying the width by the length. For a square they are equal to each other. That means each side is 8 cm. There are four sides on a square., so the perimeter (the distance around it) is 4x8 or 32 cm.
50
Its other diagonal works out as 32 cm using Pythagoras' theorem It will have 4 right angle triangles of 20 cm by 16 cm by 12 cm Its area is: 0.5*32*24 = 384 square cm Its area is also: 0.5*16*12*4 = 384 square cm
A square with a side length of 2 cm has an area of 4 square cm.
28 cm
Perimetre of squre is 4*(side) and side is 8 cm so perimetre is 4*8=32cm
The perimeter of a square of known area is 4 x sqrt area, in this case 4 x 10 = 40 cm.
Perimeter of the square: P = 4a P = 4 × 7 cm P = 28 cm
Each side is 20 cm so 20*20 = 400 square cm
If it is a 4 faced tetrahedron pyramid then its complete surface area is 4*80 =320 square centimetres
You are asking what the perimeter of a figure is when you already know it. What kind of question is that? I'll assume you mean the area of the square is 64 cm2. The area of a square in calculated by multiplying the width by the length. For a square they are equal to each other. That means each side is 8 cm. There are four sides on a square., so the perimeter (the distance around it) is 4x8 or 32 cm.
Area = pi*402 = 5026.548 square cm to 3 dp
200 cm x 80 cm = 16000 cm2 (16000 square centimetres)
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Area of square: 1/16 square cm
Its other diagonal works out as 32 cm using Pythagoras' theorem It will have 4 right angle triangles of 20 cm by 16 cm by 12 cm Its area is: 0.5*32*24 = 384 square cm Its area is also: 0.5*16*12*4 = 384 square cm