Its other diagonal works out as 32 cm using Pythagoras' theorem
It will have 4 right angle triangles of 20 cm by 16 cm by 12 cm
Its area is: 0.5*32*24 = 384 square cm
Its area is also: 0.5*16*12*4 = 384 square cm
The diagonals of a rhombus bisect one another.
The area of the rhombus is 40 square feet. To see why, Draw a rectangle encompassing the rhombus with sides parallel to the rhombus' diagonals. The rectangle has dimensions 10 ft X 8 ft = 80 square ft. Using the diagonals as dividers, each quarter of the rectangle is divided into 2 by one of the rhombus' sides. Thus the area of the rhombus is exactly half that of the encompassing rectangle.
Let the other diagonal be x:- If area is: 0.5*x*7.5 = 37.5 Then x is: 37.5/(0.5*7.5) = 10 The rhombus will then have 4 right angles with sides of 5 and 3.75 Using Pythagoras: hypotenuse of each triangle is 6.25 cm Therefore perimeter of the rhombus is: 4*6.25 = 25 cm
false
True, the diagonals of a rhombus are perpendicular bisectors of one another.
Answer63cm2. False
The diagonals of a rhombus bisect one another.
The area of the rhombus is 40 square feet. To see why, Draw a rectangle encompassing the rhombus with sides parallel to the rhombus' diagonals. The rectangle has dimensions 10 ft X 8 ft = 80 square ft. Using the diagonals as dividers, each quarter of the rectangle is divided into 2 by one of the rhombus' sides. Thus the area of the rhombus is exactly half that of the encompassing rectangle.
Let the other diagonal be x:- If area is: 0.5*x*7.5 = 37.5 Then x is: 37.5/(0.5*7.5) = 10 The rhombus will then have 4 right angles with sides of 5 and 3.75 Using Pythagoras: hypotenuse of each triangle is 6.25 cm Therefore perimeter of the rhombus is: 4*6.25 = 25 cm
True
false
True, the diagonals of a rhombus are perpendicular bisectors of one another.
Area equals base times height. The perimeter is 4 times the length of one side.
That will depend on the length of the other diagonal because area of a rhombus is 0.5*product of its diagonals.
Perimeter = 29 cm so each side is 7.25 cm. The triangle formed by the diagonal and two sides has sides of 7.25, 7.25 and 11.8 cm so, using Heron's formula, its area is 24.9 square cm. Therefore, the area of the rhombus is twice that = 49.7 square cm.
The diagonals bisect each other. Since that is true then the area of the rhombus is the sum of the two triangles. Half of one diagonal times the other diagonal.2(6x5)/2 or 6x5=30
The diagonals of a rhombus are lines drawn from one corner, or vertex, to the opposite one. They have two important properties. 1. Diagonals bisects a pair of opposite angles. 2. Diagonals are !!perpendicular!!