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∙ 14y agoThe area of the shaded region is 1265.42 meters squared, since I subtracted the two totals of both the unshaded region and the shaded region of a circle.
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∙ 14y agoArea of a circle with radius r = pir2Area of the largest circle = Area of the smallest circle + Area of the shaded regionSince areas of the smallest circle and the shaded region are 9pi and 72pi, the Area, A, of the largest circle isA = 9pi + 72pi = 81pi, where r2 = 81.Thus, the radius of the largest circle is 9
You divide the area of the shaded region by the area of the full circle. For example, if the radius of the shaded region is 2 meters, the probability would be 4pi / 36pi, or 1/9. If the shaded region is a 'slice' of the circle, the chance is just the fraction of the circle which the 'slice' is.
Area of a circle = (pi) x (radius)2Radius = 1/2 of the diameterArea of this particular circle = (pi) x (7)2 = 49 pi = 153.938 square centimeters (rounded)
If the radius of the circle is R, and the length of the flat region is c, then the area of the circle containing a flat is: A = R2 [Pi - Arcsin(c / 2R)] + [(c / 2) (R2 - (c / 2)2)1/2] After some calculus and algebra
The area of the shaded region can be gotten by multiplying the area of the circle by the subtended angle of the sector.
i know that a feasible region, is the region which satisfies all the constraints but i don't know exactly why is the unshaded region regarded as a feasible region instead of the shaded region.
Area of a circle with radius r = pir2Area of the largest circle = Area of the smallest circle + Area of the shaded regionSince areas of the smallest circle and the shaded region are 9pi and 72pi, the Area, A, of the largest circle isA = 9pi + 72pi = 81pi, where r2 = 81.Thus, the radius of the largest circle is 9
You divide the area of the shaded region by the area of the full circle. For example, if the radius of the shaded region is 2 meters, the probability would be 4pi / 36pi, or 1/9. If the shaded region is a 'slice' of the circle, the chance is just the fraction of the circle which the 'slice' is.
(pi * radius squared) * ( sector angle / 360 )
Area of a circle = (pi) x (radius)2Radius = 1/2 of the diameterArea of this particular circle = (pi) x (7)2 = 49 pi = 153.938 square centimeters (rounded)
Australia is a region that is also an entire continent.
If the radius of the circle is R, and the length of the flat region is c, then the area of the circle containing a flat is: A = R2 [Pi - Arcsin(c / 2R)] + [(c / 2) (R2 - (c / 2)2)1/2] After some calculus and algebra
The region between the Arctic Circle and the North Pole is called the Arctic region. The region between the Antarctic Circle and the South Pole is called the Antarctic region.
No, the region enclosed by a circle is not considered convex because it contains points within the circle that do not lie on the boundary of the circle. In convex regions, any line segment connecting two points inside the region will also lie completely inside the region.
the set f all points of the plane which lie either on the circle or inside the circle form the circular region
A circular region or a disk.
Simply put, the area of a shaded region can be calculated using: Area of shaded region = Total area - Area of unshaded region. Sometimes finding the area is simple, and other times, not so easy. Often , it is necessary to subdivide areas into shapes mathematics provides regular area formulas for.