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i know that a feasible region, is the region which satisfies all the constraints but i don't know exactly why is the unshaded region regarded as a feasible region

instead of the shaded region.

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Q: Why a feasible region is the unshaded region?
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What is the area of a the shaded region if the radius of the unshaded region is 9m on a circle and the radius of the entire circle is 13m?

The area of the shaded region is 1265.42 meters squared, since I subtracted the two totals of both the unshaded region and the shaded region of a circle.


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In a system of nonlinear inequalities the solution set is the region where the shaded regional overlap?

The answer depends on which area is shaded for each inequality. I always teach pupils to shade the unwanted or non-feasible region. That way the solution is in the unshaded area. This is much easier to identify than do distinguish between a region which is shaded three times and another which is shaded four times.


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Yes they will. That is how the feasible region is defined.


What is the minimum value of 6x plus 5y in the feasible region?

Since there is no feasible region defined, there is no answer possible.


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The answer depends on what the feasible region is and on what operator is between 6x and 8y.


What is the minimum value of 6x plus 5y in the feasible region excluding point (0 0)?

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What is the minimum value of 3x plus 3y in the feasible region?

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Is Feasible region is necessary to be a convex set?

Yes, in optimization problems, the feasible region must be a convex set to ensure that the objective function has a unique optimal solution. This is because convex sets have certain properties that guarantee the existence of a single optimum within the feasible region.


What is the value of 6x 5y at point D in the feasible region?

Given definitions, or descriptions at least, of "point D" and "the feasible region",I might have had a shot at answering this one.