4cm
180cm3
The area of any triangle is (1/2) x (length of the base) x (height). We're sure you can take it from there.
1/2*6*4 = 12 square cm
The area of a rectangle of sides 9cm and 10cm is:9cm x 10cm = 90cm2This is equivalent to 0.009m2
4cm
180cm3
Area of a triangle = (1/2) x (base) x (height) Can you handle it from there ?
The area of any triangle is (1/2) x (length of the base) x (height). We're sure you can take it from there.
For it to be a right angle triangle the 3rd side must be 5cm
1/2*6*4 = 12 square cm
Yes (apart from units):If the side of a square is 4cm then itsperimeter is 4cm + 4cm + 4cm + 4cm = 4 x 4cm = 16cm;area is 4cm x 4cm = 16cm2
The area of a rectangle of sides 9cm and 10cm is:9cm x 10cm = 90cm2This is equivalent to 0.009m2
Area = 1/2 (base x height) If the triangle is sitting on the 9cm side, then 72 = 1/2 ( 9 x height ) Height = 16 cm There are an infinite number of ways to draw the remaining two sides such that the height of the triangle is 16 cm. So the given information doesn't define a unique perimeter.
The area of a right-angle triangle is half of the area of a rectangle 8cm x 4cm. Find the rectangle area and divide by half to find the area of the right-angle triangle. Therefore: 8 x 4 / 2 = 16cm2 * * * * * The above answer assumes that the two given lengths are the shorter legs of the triangle. It is, however, possible that these are the hypotenuse and one leg. In that case, the second leg is 4*sqrt(2) cm and the area of the triangle is 4 * 4*sqrt(2) / 2 = 8*sqrt(2) = 11.31 cm2.
To find the area of a rectangle, you multiply the length by the width. In this case, the width is 7cm and the length is 9cm. So, the area would be 7cm x 9cm = 63 square centimeters.
The formula to find the area of a triangle is 1/2bhb = baseh = heightSo, in order to work out the area of a triangle with a base of 4cm and a height of 7cm...7 x 4 = 2828 / 2 = 14The area is 14cm2