To find the area of a triangle with sides of lengths 24, 76, and 67, you can use Heron's formula. First, calculate the semi-perimeter ( s = \frac{24 + 76 + 67}{2} = 83.5 ). Then, the area ( A ) can be found using the formula ( A = \sqrt{s(s-a)(s-b)(s-c)} ), where ( a = 24 ), ( b = 76 ), and ( c = 67 ). Plugging in the values, the area is approximately 672 square units.
Area = 1/2*8*12*sin150 = 24 square units
It is: 24 square units
The sides are 6 and 8 and so the area is 0.5*6*8 = 24 cm2.
A triangle with side lengths of 24, 24, and 4 is an isosceles triangle, where two sides are equal (24) and the base is 4. To confirm that these lengths can form a triangle, we can apply the triangle inequality theorem, which states that the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 24 + 24 > 4, 24 + 4 > 24, and 24 + 4 > 24 hold true, so the triangle is valid. However, it will be a very narrow triangle, almost degenerate, as the two longer sides are significantly larger than the base.
Yes, it is.
Area = 1/2*8*12*sin150 = 24 square units
It is: 24 square units
6+8+10=24The perimeter of the triangle is 24 inchesThe perimeter is all the side lengths added up, so that triangle would have a perimeter of 24 inches.6+8+10=24 inches
The sides are 6 and 8 and so the area is 0.5*6*8 = 24 cm2.
A triangle with side lengths of 24, 24, and 4 is an isosceles triangle, where two sides are equal (24) and the base is 4. To confirm that these lengths can form a triangle, we can apply the triangle inequality theorem, which states that the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 24 + 24 > 4, 24 + 4 > 24, and 24 + 4 > 24 hold true, so the triangle is valid. However, it will be a very narrow triangle, almost degenerate, as the two longer sides are significantly larger than the base.
Yes, it is.
Forget about the area and use Pythagoras' theorem: 62+82 = 100 and the square root of this is 10 New perimeter = 6+8+10 = 24 cm
No, because 8 isn't a factor of 30.
First make sure that this is a valid right triangle Since 25 x 25 = (24 x 24) + (7 x 7) we are assured that it is truly a right triangle with 25 as the hypotenuse and the other two sides being 7 and 24 linear units. Then we can use the formula for area of triangle as (1/2) x base x height which in our case would be (1/2) x 7 x 24 = 7 x 12 = 84 square units
If a triangle with a perimeter of 24 cm is an equilateral triangle, then each of its 3 sides will be 8 cm in length
It's half the size of a quadrilateral with 24 square units ------------ One type of triangle with an area of 12 square units is the isosceles triangle with two 5-unit sides and one 6-unit side.
24