The area is 40cm2
440
195.5
Use Pythagoras' Theorem : In a right angled triangle the square of the hypotenuse is equal to the sum of the squares of the other two sides. Let H be the hypotenuse then :- H2 = 152 + 82 = 225 + 64 = 289 Then H = √289 = 17cm
195.5
better question what shape is it
If the sides are 10cm, 17cm and 21cm, the three angles are approx 28, 53 and 99 degrees. It is an obtuse angled triangle.
440
=17cm
a is one of the equal sides of the iscosceles triangle b is the base perimeter is a + a + b = 46cm a = b + 5cm subsitute a for b + 5cm in the perimeter equation b + 5cm + b + 5cm + b = 46cm This simplifies down to 3b + 10cm = 46cm subtract 10cm from both sides of the equation 3b + 10cm - 10cm = 46cm - 10cm 3b = 36cm Then divide each side of the equation by 3 3b ÷ 3 = 36cm ÷ 3 b = 12cm Subsitute b back into a = b +5cm a = 12cm + 5cm a = 17cm So you have 2 sided with the length of 17cm and the base with the length of 12cm
60 cm2
28.611
should be round 10cm - 17cm
If two sides of a triangle have lengths of 5cm and 12cm, then the third side can have any length that's more than 7cm and less than 17cm. If the third side is 13cm, then the triangle is a right triangle.
2m 17cm
195.5
Use Pythagoras' Theorem : In a right angled triangle the square of the hypotenuse is equal to the sum of the squares of the other two sides. Let H be the hypotenuse then :- H2 = 152 + 82 = 225 + 64 = 289 Then H = √289 = 17cm
195.5