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What is the perimeter and area of a rectangle that has a length of 12 inches and a width of 10 and a half inches?
Perimeter = 2*(L + W) = 2*(12 + 10.5) = 2*22.5 = 45 inches. Area = 12*10.5 = 126 square inches.
What is the area of a rectangle with a perimeter of 36 inches and a length of 5 inches?
With a perimeter of 36, and a known width of 5, that means the length is 13. This makes the area 65.Perimeter = (2 x Length) + (2 x Width)Width = [Perimeter - (2 x Length)]/2= [36 -(2 x 13)]/2= (36 - 26)/2= 10/2= 5 inchesArea = Length x Width= 13 x 5= 65 square inches
What is the area of Perimeter of rectangle s is 16 inches?
If the perimeter of a rectangle is 16 inches, the formula for the perimeter is ( P = 2(l + w) ), where ( l ) is the length and ( w ) is the width. Setting the perimeter equal to 16 gives us ( l + w = 8 ). The area ( A ) of the rectangle is calculated as ( A = l \times w ). Without specific dimensions for length and width, the area can vary; however, the maximum area occurs when the rectangle is a square with each side measuring 4 inches, giving an area of ( 16 ) square inches.
What measurements do you need to find the area and perimeter of a rectangle how would you use these measurements to find the area and perimeter of a rectangle?
you need length and width length multiply width = area length + length + width + width = perimeter
What is the difference between perimeter and area of polygon?
perimeter is the measure around the figure; area is the measure within the figure formula: perimeter: length+length+width+width=perimeter (for square or rectangle) area: length times width= area ( for square or rectangle)
What are the perimeter and area of a rectangle with the length of 5 in and a width of 7 in?
Perimeter = 24 inches Area = 35 square inches
What is the perimeter and area of a rectangle with 5 in length and 11 in width?
Perimeter = 32 inches. Area = 55 square inches.
What is the perimeter and area of 3in and 9in?
If that's a rectangle, the perimeter is 24 inches and the area is 27 square inches.
How do you get the area if you have the width and the perimeter?
Perimeter = 2 lengths + 2 widths 1/2 perimeter = length + width Length = 1/2 perimeter - width Area = length x width That's (1/2 perimeter - width) x (width) .
What is the perimeter and area of a rectangle that has a length of 12 inches and a width of 10 and a half inches?
Perimeter = 2*(L + W) = 2*(12 + 10.5) = 2*22.5 = 45 inches. Area = 12*10.5 = 126 square inches.
What is the area of a rectangle with a perimeter of 36 inches and a length of 5 inches?
With a perimeter of 36, and a known width of 5, that means the length is 13. This makes the area 65.Perimeter = (2 x Length) + (2 x Width)Width = [Perimeter - (2 x Length)]/2= [36 -(2 x 13)]/2= (36 - 26)/2= 10/2= 5 inchesArea = Length x Width= 13 x 5= 65 square inches
What measurements do you need to find the area and perimeter of a rectangle how would you use these measurements to find the area and perimeter of a rectangle?
you need length and width length multiply width = area length + length + width + width = perimeter
What is the difference between perimeter and area of polygon?
perimeter is the measure around the figure; area is the measure within the figure formula: perimeter: length+length+width+width=perimeter (for square or rectangle) area: length times width= area ( for square or rectangle)
The perimeter of a rectangle is 26 inches the width of the rectangle is 5 inches what is the area of the rectangle?
The area of the rectangle is: 5 times 8 = 40 square inches
How do you find area when given perimeter and width?
If you are given the width and the perimeter, then figure out what the length is then calculate the area... hope this helps :)
A rectangle has a length of six cm What is its width if its perimeter and area are the same number?
18cm is the area and perimeter. the width is 3cm.
How do you find the perimeter of a rectangle if you have the length and the area?
Area = Length*Width so Width = Area/Length. Therefore the Width can be calculated. Then, perimeter = 2*(Length + Width) and everything on the right hand side of the equation is known so the perimeter can be calculated.
