Q: What is the area of the largest circle that can be draw in a square that sides is 32.5 centimeters?

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16.25 cm will be the radius of the circle (32.5 divided by 2) Area of a circle = pi*radius2 = pi*16.252 = 51.05088062 square centimetres So the answer is 51 square metres correct to two significant figures.

The sides of the Square.

25 square centimeters.

324 square centimeters.

pi*radius2 = 169*pi Divide both sides by pi then square root both sides to find the radius: radius = 13 and 2*13 = a diameter of 26 cm

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16.25 cm will be the radius of the circle (32.5 divided by 2) Area of a circle = pi*radius2 = pi*16.252 = 51.05088062 square centimetres So the answer is 51 square metres correct to two significant figures.

Largest area = pi*182 = 1017.876 square cm to 3 dp

pi*r2 = 28.26 Divide both sides by pi: r2 = 8.995437384 Square root both sides: radius = 2.999239468 diameter = 2*radius: diameter = 5.998478935 or 6 centimeters to the nearest cm.

The diameter length of the circle would be the same as the side length of the square. If a is the side of the square, then the radius is a/2, and the area of the circle would be (1/4)(pi)(a^2).

NO. A square has 4 equal sides with the sides perpendicular each other. A circle has infinite sides.

The sides of the Square.

It would be 32.8 centimeters. A square has 4 sides and equal sides. So 8.2 x 4 equals 32.8

25 square centimeters.

324 square centimeters.

No, because the two lowest sides have equal more than the largest when added.

pi*radius2 = 169*pi Divide both sides by pi then square root both sides to find the radius: radius = 13 and 2*13 = a diameter of 26 cm

A circle of radius, r, has area pi r2. The largest square inside it is made up of four isosceles triangles whose equal sides are of length, r, and thus has area 1/2 r2. Thus the area of the contained square is 2 r2.