Largest area = pi*182 = 1017.876 square cm to 3 dp
NO. A square has 4 equal sides with the sides perpendicular each other. A circle has infinite sides.
Do you mean perimeter?The sum of the lengths of the four sides of a square is the perimeterThe total length of the circumference of a circle is its perimeter
the area of a square is 49m^2 what is the length of one of its sides
It is a straight line within the circle that touches both sides of the circumference and the largest chord is the circle's diameter.
A circle is not a polygon, because a circle has no sides that are straight line segments.
The diameter length of the circle would be the same as the side length of the square. If a is the side of the square, then the radius is a/2, and the area of the circle would be (1/4)(pi)(a^2).
NO. A square has 4 equal sides with the sides perpendicular each other. A circle has infinite sides.
The sides of the Square.
π × (16.25cm)2 = 264.0625π cm2 ≈ 829.5761cm2
NO! DEFINITELY NOT!!! A circle has NO sides at all! A quadrilateral has four sides. A quadrilateral is a polygon with four sides. For example: the square, the rhombus, the rectangle etc.. A circle measures 360 centimetres in circumference. This so because there has to be some way to measure the circle, and mathematicians came up with this strategy, I don't know how (yet). The point is the circle cannot have sides or angles because it is completely round, and a round figure cannot have sides nor angles.
16.25 cm will be the radius of the circle (32.5 divided by 2) Area of a circle = pi*radius2 = pi*16.252 = 51.05088062 square centimetres So the answer is 51 square metres correct to two significant figures.
324 square centimeters.
A circle of radius, r, has area pi r2. The largest square inside it is made up of four isosceles triangles whose equal sides are of length, r, and thus has area 1/2 r2. Thus the area of the contained square is 2 r2.
The largest rectangle would be a square. If the circle has radius a, the diameter is 2a. This diameter would also be the diameter of a square of side length b. Using the Pythagorean theorem, b2 + b2 = (2a)2. 2b2 = 4a2 b2 = 2a2 b = √(2a2) or a√2 = the length of the sides of the square The area of a square of side length b is therefore (√(2a2))2 = 2a2 which is the largest area for a rectangle inscribed in a circle of radius a.
Do you mean perimeter?The sum of the lengths of the four sides of a square is the perimeterThe total length of the circumference of a circle is its perimeter
24KM
A square with sides of 0.4985 units will fit in the circle.