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Largest area = pi*182 = 1017.876 square cm to 3 dp

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12y ago

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What is the area of the largest circle that fits inside a square with 4 sides?

The diameter length of the circle would be the same as the side length of the square. If a is the side of the square, then the radius is a/2, and the area of the circle would be (1/4)(pi)(a^2).


If you have a square inscribed in a circle what is the diameter of the circle congruent to?

The sides of the Square.


Is a circle a 2 dimensional square?

NO. A square has 4 equal sides with the sides perpendicular each other. A circle has infinite sides.


What is the area of the largest circle that can be draw in a square that sides is 32.5 centimeters?

π × (16.25cm)2 = 264.0625π cm2 ≈ 829.5761cm2


Does a circle have 4 sides?

NO! DEFINITELY NOT!!! A circle has NO sides at all! A quadrilateral has four sides. A quadrilateral is a polygon with four sides. For example: the square, the rhombus, the rectangle etc.. A circle measures 360 centimetres in circumference. This so because there has to be some way to measure the circle, and mathematicians came up with this strategy, I don't know how (yet). The point is the circle cannot have sides or angles because it is completely round, and a round figure cannot have sides nor angles.


What is the Are of a largest circle that can be draw in a square that sides is 32.5 centimeters?

16.25 cm will be the radius of the circle (32.5 divided by 2) Area of a circle = pi*radius2 = pi*16.252 = 51.05088062 square centimetres So the answer is 51 square metres correct to two significant figures.


What is the area of a square if sides measures 18cm?

324 square centimeters.


Find the area of the largest square incribed in a circle?

A circle of radius, r, has area pi r2. The largest square inside it is made up of four isosceles triangles whose equal sides are of length, r, and thus has area 1/2 r2. Thus the area of the contained square is 2 r2.


Find the dimensions of the rectangle of largest area that can be inscribed in a circle of radius a?

The largest rectangle would be a square. If the circle has radius a, the diameter is 2a. This diameter would also be the diameter of a square of side length b. Using the Pythagorean theorem, b2 + b2 = (2a)2. 2b2 = 4a2 b2 = 2a2 b = √(2a2) or a√2 = the length of the sides of the square The area of a square of side length b is therefore (√(2a2))2 = 2a2 which is the largest area for a rectangle inscribed in a circle of radius a.


What is called the length of the sides of a square and a circle?

Do you mean perimeter?The sum of the lengths of the four sides of a square is the perimeterThe total length of the circumference of a circle is its perimeter


What size square needed to fit a .705 diameter circle?

A square with sides of 0.4985 units will fit in the circle.


What are the dimensions of largest square that can be inscribed in a circle?

The diagonal of the square is the diameter of the circle (think about it!) so the sides of the square can be pythagorassed ie the square of the diagonal is twice the square of a side. As an example, consider a circle of diameter 50 units. the square of this is 2500 so every side of the square is the square root of 1250 units which equals sqrt 625 x sqrt 2 or 25 root 2 ie 35.355339 units, or 70.71% of the diameter of the circle. More basically, the diagonal is the hypotenuse of a 45/45/90 triangle so the sides are in the ratio 1/1/root2 or if you want the hypotenuse to be 1, the sides would be (root 2)/2. Either way, the sides are root2 times the radius of the circle, which is of course half the diameter. This is in full agreement with the 25 root2 calculated above for a 50 unit diameter circle.