What is the area of a regular pentagon with side length of 9.4 feet and an apothem length of 6.5 feet
85.30
I use the formula 5S2/4 tan36 which when S = 4 gives an area of 27.53 sqft
21ft
Area = 1,918,570 ft2
What is the area of a regular pentagon with side length of 9.4 feet and an apothem length of 6.5 feet
85.30
I use the formula 5S2/4 tan36 which when S = 4 gives an area of 27.53 sqft
15.5 ft.
A regular pentagon has a perimeter of 5s. We set this equal to 15, and solve for s, and convert to yards.5s = 15s = 33 feet converted to yards is 3/3 = 1 yard.
Providing that it is a regular 5 sided pentagon then the perimeter is 5*921.6 = 4608 feet
If the pentagon is 'regular', we can ignore the digestive implications and focus onthe geometric ones, namely, that each of its five sides has the same length. Sinceone of them is 13 feet long, they all are, and the perimeter is 13 x 5 = 65 feet.
You cannot. Square feet is a measure of area while regular feet is a length. There is no direct conversion possible.
That is impossible. Square feet show an area and "regular" feet is a length measure.
The Pentagon isn't in Washington DC, it's in Arlington, Virginia, but regardless of that, the pentagon is a five sided building with each side being 921 feet in length. 921 times 5 is 4605. The parameter of the pentagon is 4605 feet.
21ft
Area = 139.36 ft2