What is the area of a regular pentagon with side length of 9.4 feet and an apothem length of 6.5 feet
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Area = 440.44 sq feet
A regular pentagon has five (5) equilateral triangles within it. Find the area of each triangle (1/2bh where b is the base of the triangle or the length of a side of the pentagon, and h is the height of the triangle or the apothem of the pentagon) and multiply the area of the triangle times five (5).
The answer is 171.275*apex*
85.30
13
Area = 440.44 sq feet
regular pentagon area of 12 000 m2 and an apothem of 40 m regular pentagon area of 12 000 m2 and an apothem of 40 m need to figure it out from area 12000 m2
A regular pentagon has five (5) equilateral triangles within it. Find the area of each triangle (1/2bh where b is the base of the triangle or the length of a side of the pentagon, and h is the height of the triangle or the apothem of the pentagon) and multiply the area of the triangle times five (5).
The answer is 171.275*apex*
85.30
13
A regular pentagon with a radius (apothem) of 5.1 units cannot have sides of 7.5 units and, conversely, a regular pentagon with sides of length 7.5 units cannot have a radius of 5.1 units. The figure is, therefore, impossible.
The area of a regular pentagon with a radius of 7 is 10.1716. If the radius was 5, the area would be 7.26543.
If 6 is the side of a regular pentagon, the area is 61.937
Apothem length: 4.82 35.35 square units APEX
I use the formula 5S2/4 tan36 which when S = 4 gives an area of 27.53 sqft
The formula for finding the area of a regular pentagon is: A= 1/4*{sqrt[5(5+2sqrt(5)]}*a^2 where * means multiply, ^2 means 't the power of 2 or squared) You only need the length of the side. So the area of this pentagon is given by A= 1/4{sqrt[5(5+2sqrt(5)]}*.9^2 =1/4*(6.8819)*0.81 = 1.3936 sq mm.