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What is the area of the triangle formed by the line 3x -7y plus 4 equals 0 and the axes on the Cartesian plane showing work?
Suppose the line meets the x and y axes at A and B (respectively). Then
at A, x = 0 =-> -7y + 4 = 0 so y = 4/7. Therefore A = (0, 4/7) => |OA| = 4/7, and
at B, y = 0 => 3x + 4 = 0 so x = -4/3. Therefore B = (-4/3, 0) => |OB| = 4/3.
AOB is a right angled triangle with the right angle at O.
Therefore area AOB = 1/2*|OA|*|OB| = 1/2*4/7*4/3 = 8/21 square units.
What else can I help you with?
Which type of triangle is formed with the points A(1 7) B(-2 2) and C(4 2) as its vertices?
It appears to be an isosceles triangle when plotted on the Cartesian plane
What is the area of a triangle formed by the line 3x -7y plus 4 equals 0 when it meets the x and y axes on the Cartesian plane?
Equation of line: 3x-7y+4 = 0 Base of triangle: 4/3 Height of triangle: 4/7 Area of triangle: 0.5*4/3*4*7 = 8/21
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Which type of triangle is formed with the points A(1 7) B(-2 2) and C(4 2) as its vertices?
It appears to be an isosceles triangle when plotted on the Cartesian plane
What is the area of a triangle formed by the line 3x -7y plus 4 equals 0 when it meets the x and y axes on the Cartesian plane?
Equation of line: 3x-7y+4 = 0 Base of triangle: 4/3 Height of triangle: 4/7 Area of triangle: 0.5*4/3*4*7 = 8/21
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