We can't tell the difference between the "base" and the "width" of a triangle,
so we're frankly stumped.
The area of triangle is : 12.0
Area of a triangle = b x h/2, where b is the base and h is height. To solve for b, manipulate the formula to b = 2A/h, where A is the area. b = 2A/h = 2(3ft2)/2ft = 3ft
The answer depends on what the shape is: a 2-dimensional triangle, a 3-dimensional cuboid, an ellipsoid or something else.
The area of rectangle is : 30.0
The figures given in the question cannot be a triangle, leave alone a right angled triangle.
9feet
The area of triangle is : 12.0
To do this just multiply together 2ft(*)2ft = 4ft^2 or four feet squared area=lenth times width
Easy. Width = 2ft, Length = 4 ft, therefore the Area = 8 ft.
It is not possible to answer the question with only the lengths of two sides of a triangle.
Area of a triangle = b x h/2, where b is the base and h is height. To solve for b, manipulate the formula to b = 2A/h, where A is the area. b = 2A/h = 2(3ft2)/2ft = 3ft
The width is either 2ft or 7ft.
the width is 1 and the length is 2. 2 multipleyed by 1 equals 2...
To find the area of a rectangle, you multiply its length by its width. In this case, the length is 7 feet and the width is 2 feet. Therefore, the area of the rectangle is 7 feet x 2 feet = 14 square feet.
The answer depends on what the shape is: a 2-dimensional triangle, a 3-dimensional cuboid, an ellipsoid or something else.
The area of rectangle is : 30.0
Depends length-25ft width-10ft length - 125ft width - 2ft length - 50ft width- 5ft