Easy. Width = 2ft, Length = 4 ft, therefore the Area = 8 ft.
10 in. A+LS
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
if the width is 3.5 then the length is 10 10 = 3 +2(3.5) 10 x 3.5 = 35
For a rectangle, area equals length times width. To find the length given the width and area, divide the area by the width.
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle
Assuming you're talking about a rectangle: Diagonal squared = length squared + width squared (Pythagoras) so: Length squared = diagonal squared - width squared ie length = sqrt (diagonal squared - width squared)
10 in. A+LS
Lengthxwidth=area You multiply the length times the width and then you put the answer in squared units
You square the width and subtract it from the diagonal squared. Then find the square root of this number, this number is now the length.
length x width Example: A rectangle has a length of 24m and a width of 48m. What is its area? l x w= 24m(length) x 48m(width/breadth) = 1152m2 (meters squared)
the length of a rectangle is 8 more than the width. the area os 345 centimeters. find the length and width of the rectangle
Since a square is also a rectangle the formula is length times width or the length of one side squared.
Multiply the length by the width: 7 x 6 = 42. If the the units of length and width are metres (m) then the are would be metres squared (m2).
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.
For a rectangle, area equals length times width. To find the length given the width and area, divide the area by the width.
if the width is 3.5 then the length is 10 10 = 3 +2(3.5) 10 x 3.5 = 35