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What is the area under the standard normal distribution curve between z0.75 and z1.89?

0.1972


Why does a researcher want to go from a normal distribution to a standard normal distributio?

A normal distribution simply enables you to convert your values, which are in some measurement unit, to normal deviates. Normal deviates (i.e. z-scores) allow you to use the table of normal values to compute probabilities under the normal curve.


Find the area under a normal distribution curve that lies within one standard deviation of the mean is approximattely?

The area under N(0,1) from -1 to 1 = 0.6826


What does the curve of the standard normal distribution represent?

The curve of the standard normal distribution represents the probability distribution of a continuous random variable that is normally distributed with a mean of 0 and a standard deviation of 1. It is symmetric around the mean, illustrating that values closer to the mean are more likely to occur than those further away. The area under the curve equals 1, indicating that it encompasses all possible outcomes. This distribution is commonly used in statistics for standardization and hypothesis testing.


Find the area under the normal distribution curve between z equals 1.23 and z equals 1.90?

Look in any standard normal distribution table; one is given in the related link. Find the area for 2.43 and 1.52; then take the area for 2.43 and subtract the area for 1.52 and that will be the answer. Therefore, .9925 - .9357 = .0568 = area under the normal distribution curve between z equals 1.52 and z equals 2.43.

Related Questions

The total area under a normal distribution is infinite?

The total area under a normal distribution is not infinite. The total area under a normal distribution is a continuous value between any 2 given values. The function of a normal distribution is actually defined such that it must have a fixed value. For the "standard normal distribution" where μ=0 and σ=1, the area under the curve is equal to 1.


What is the area under the standard normal distribution curve between z1.50 and z2.50?

~0.0606


What is the area under the standard normal distribution curve between z0.75 and z1.89?

0.1972


What is the significance of the constant 1/sqrt(2pi) in the formula for the standard normal distribution?

The constant 1/sqrt(2pi) in the formula for the standard normal distribution is significant because it normalizes the distribution so that the total area under the curve equals 1. This ensures that the probabilities calculated from the distribution are accurate and meaningful.


Are these true of normal probability distribution IIt is symmetric about the mean TTotal area under the normal distribution curve is equal to 1 DDistribution is totally described by two quantities?

Yes, it is true; and the 2 quantities that describe a normal distribution are mean and standard deviation.


What is the area under standard normal distribution curve between z equals 0 and z equals 2.16?

0.4846


Why does a researcher want to go from a normal distribution to a standard normal distributio?

A normal distribution simply enables you to convert your values, which are in some measurement unit, to normal deviates. Normal deviates (i.e. z-scores) allow you to use the table of normal values to compute probabilities under the normal curve.


What is the area under standard normal distribution curve between z equals 0 and z equals -2.16?

2.16


The distribution of sample means is not always a normal distribution Under what circumstances will the distribution of sample means not be normal?

The distribution of sample means will not be normal if the number of samples does not reach 30.


He area under the standard normal curve is?

The area under the standard normal curve is 1.


Is the area under the standard normal distribution to the left of z equals 0 negative?

The Z value is negative, but area is always positive.


Find the area under a normal distribution curve that lies within one standard deviation of the mean is approximattely?

The area under N(0,1) from -1 to 1 = 0.6826