The new mean would be 7. The mean is the average of the data. (x1+x2+x3+x4+x5+x6+x7+x8+x9+x10)/10=21 [(x1/3)+(x2/3)+(x3/3)+(x4/3)+(x5/3)+(x6/3)+(x7/3)+(x8/3)+(x9/3)+(x10/3)]/10=? [(1/3)(x1+x2+x3+x4+x5+x6+x7+x8+x9+x10)]/10=? [(x1+x2+x3+x4+x5+x6+x7+x8+x9+x10)/10]/3= 21/3=7
The pattern is x1, x2, x3, x4, x5, x6.... The next two numbers are 120, 720.
You can solve this to the accuracy of your liking by using Newton's method: xn+1 = xn - f(xn) / f'(xn) In this case, we'll say f(x) = x2 - cos(x) f'(x) would then be 2x + sin(x) Let's take a rough guess, and start with x0 = 0.5 x1 = 0.5 - (0.52 - cos(0.5)) / (2(0.5) + sin(0.5)) = 0.92420692729319751536 x2 = x1 - (x12 - cos(x1)) / (2x1 + sin(x1)) = 0.82910575599741780916 x3 = x2 - (x22 - cos(x2)) / (2x2 + sin(x2)) = 0.82414613172819520712 x4 = x3 - (x32 - cos(x3)) / (2x3 + sin(x3)) = 0.8241323124099124229 x5 = x4 - (x42 - cos(x4)) / (2x4 + sin(x4)) = 0.82413231230252242297 x6 = x5 - (x52 - cos(x5)) / (2x5 + sin(x5)) = 0.82413231230252242296 Now we can test our answer: 0.824132312302522422962 = 0.67919406818110235182 cos(0.82413231230252242296) = 0.67919406818110235183 So we're accurate to the nearest ten quintillionth.
First of all, find the total number of not-necessarily distinguishable permutations. There are 12 letters in hippopotamus, so use 12! (12 factorial), which is equal to 12 x 11x 10 x9 x8 x7 x6 x5 x4 x3 x2 x1. 12! = 479001600.Then count the of each letter and calculate how many permutations of each letter can be made. For example, here is 1 h, so there is 1 permutation of 1 h.H 1I 1P 60 2T 1A 1M 1U 1S 1Multiply these numbers together. 1 x1 x6 x2 x1 x1 x1 x1 x1 = 12Divide 12! by this number. 479001600 / 12 = 39,916,800 Distinguishable Permutations.
x5 is an expression: there can be no answer to it.
x1/5
(x1+x2+...+x5)/5 = 34 (x1+x2+...+x5)= 5 * 34 = 170 [(x1+x2+...+x5) + x6]/6 = 35 170 + x6 = 6*35 = 210 x6 =210-170=40 Answer is 40
45
The new mean would be 7. The mean is the average of the data. (x1+x2+x3+x4+x5+x6+x7+x8+x9+x10)/10=21 [(x1/3)+(x2/3)+(x3/3)+(x4/3)+(x5/3)+(x6/3)+(x7/3)+(x8/3)+(x9/3)+(x10/3)]/10=? [(1/3)(x1+x2+x3+x4+x5+x6+x7+x8+x9+x10)]/10=? [(x1+x2+x3+x4+x5+x6+x7+x8+x9+x10)/10]/3= 21/3=7
x3/x1/2 = x5/2.
set of items arranged with 5 coords (x1,x2,x3,x4,x5)
okay... took me ages to figure out how to finish it but... up(X3), Right(X5), Up(X2), Left(X1), Down(X4), Right(X2), Down(X1), Left(X1), Right(X1), Down(X1), Left(X1), Down(X1), Right(X1), Down(X1), Left(X1), Down(X3), Right(X2), Down(X1), Right(X1), Down(X2), Left(X2), Up(X1), Right(X1), Down(X4), Right(X1), Up(X2), Left(X2), Down(X2), Right(X1) and finally Up(X1) :) code for level 30 is 676534
It is pretty much impossible
do i need to change the timing chain on my bmw x5 its done 118000
The pattern is x1, x2, x3, x4, x5, x6.... The next two numbers are 120, 720.
How do you change a front blinker bulb for a BMW X5 2001?
GCF of variables with exponents The GCF is the common variable with smallest exponent. example 9x4 - 27x6 the gcf is 9X4 because: 9x4 (1-3x2) = 9x4 - 27x6 In the same way: X5 is the GCF of X10 + x5 -x6 Because X5 ( X5 + 1 -x1) = X10 + x5 -x6 Remember the exponent rule if you are multiplyin the same base, you keep the base and add the exponents Hope this helps Btw this does not help me! anna