79+82+93+91+100=445/5=89
79
The prime numbers between 50 and 100 are 53, 59, 61, 67, 71, 73, 79, 83, 89, and 97.
To find Stacey's first test score, we can use the formula for average: (sum of all scores) / (total number of scores). Stacey's total score on three tests is 84 x 3 = 252. Her last two test scores total 79 + 93 = 172. To find her first test score, we subtract the total of the last two tests from the total score: 252 - 172 = 80. Therefore, Stacey's first test score was 80.
The average of 79, 84, 82, and 87 is 83.
It is: 79-38 = 41
79.
79
53 59 61 67 71 73 79 83 89 97.
The prime numbers between 50 and 100 are 53, 59, 61, 67, 71, 73, 79, 83, 89, and 97.
To find the average, add the scores and divide the sum by how many scores you are adding: 81 + 76 + 91 + 73 + 79 = 400 ÷ 5 = 80.
yes it is
To find Stacey's first test score, we can use the formula for average: (sum of all scores) / (total number of scores). Stacey's total score on three tests is 84 x 3 = 252. Her last two test scores total 79 + 93 = 172. To find her first test score, we subtract the total of the last two tests from the total score: 252 - 172 = 80. Therefore, Stacey's first test score was 80.
The prime numbers between 10 and 100 are 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, and 97.
The arithmetic mean is 79.
If it is a small list of scores, like 6 of them, write them in a list, for example: 96, 87, 80, 79, 75, 75 Find the 'middle' which will occur BETWEEN two numbers 96, 87, 80 (middle) 79, 75, 75. Average the two numbers on either side of the 'middle.' In this example (80 + 79) / 2 = 79.5 If the list is larger find the middle by dividing the total number of cases by 2. In this example 6 / 2 = 3. The median will be the middle BETWEEN the 3rd and 4th score. (Average the 3rd and 4th score)
score y 87
92.5 is the average.