79
79+82+93+91+100=445/5=89
The average of 79, 84, 82, and 87 is 83.
79.
To calculate the mean, add all the numbers (76 + 82 + 73 + 93 + 91 + 81 + 79 + 86 + 84 = 765) and divide by the total count (9), resulting in a mean of 85. The median, when the numbers are arranged in order (73, 76, 79, 81, 82, 84, 86, 91, 93), is 82. The mode does not exist as all numbers appear only once. The range is 93 - 73 = 20, and the standard deviation is approximately 6.07.
If final is 25% of grade and your average was 82 before final that part is 75%. So we have (.75(82) + .25 (73)) = 80
79+82+93+91+100=445/5=89
The average of 79, 84, 82, and 87 is 83.
79.
If final is 25% of grade and your average was 82 before final that part is 75%. So we have (.75(82) + .25 (73)) = 80
Your average score would be 80.
To calculate the mean, add all the numbers (76 + 82 + 73 + 93 + 91 + 81 + 79 + 86 + 84 = 765) and divide by the total count (9), resulting in a mean of 85. The median, when the numbers are arranged in order (73, 76, 79, 81, 82, 84, 86, 91, 93), is 82. The mode does not exist as all numbers appear only once. The range is 93 - 73 = 20, and the standard deviation is approximately 6.07.
82 multiplied by 79 is 6,478.
The median is the middle score in a set of data which is organised ascending (lowest to highest). In your set of data, it appears that this has already been done, which takes care of the first step. Then we count up the number of scores that have been recorded. In your case, this would be six. Since this is an even number, we take the 3rd and 4th scores, and find the average of them. So in this case:64 73 79 82 87 11079+82 = 161161 / 2 =80.5Therefore 80.5 is our median.However, in a case where there is an odd number of scores, the middle number should be selected (i.e. when there is nine scores the fifth should be selected).
1, 73 1, 2, 41, 82
That your intelligence is below the average level. An IQ of 100 is average regardless of race, ethnicity, gender, or age.
It is 20 points below average.
82