Vertex = (0,0)
Line of symmetry = y axis
You should of known that as this function is only X^2
It has y-axis symmetry. anyfunction with only x^2 and its coefficient has y-axis. These are called even fuctions. Therefore, it also might be called evensymmetry.
y = 3x2+2x-1 Line of symmetry: x = -1/3 Vertex coordinate: (-1/3, -4/3)
Forget about thw value of pi because it has nothing to do with the question. y = x2-8x+1 can be expressed as y = (x-4)2-15 Information about the vertex and line of symmetry can be extracted from the rearranged equation such as:- Vertex: (4, -15) Line of symmetry: x = 4
An isosceles triangle has one line of symmetry, which is drawn from the noncongruent side to the opposite vertex, and does not have a rotation symmetry.
From each vertex to its opposite vertex. These will be centered on a shared point at the center of the hexagon. Each complete line will be a line of symmetry for the hexagon.
A line of symmetry must go from one vertex to the midpoint of the opposite side.
In the form y = ax² + bx + c the axis of symmetry is given by the line x = -b/2a The axis of symmetry runs through the vertex, and the vertex is given by (-b/2a, -b²/4a + c). For y = 2x² + 4x - 10: → axis of symmetry is x = -4/(2×2) = -4/4 = -1 → vertex = (-1, -4²/(4×2) - 10) = (-1, -16/8 - 10) = (-1, -12)
It is (-1, 3).
K
2
How about y = (x - 2)2 = x2 - 4x + 4 ? That is the equation of a parabola whose axis of symmetry is the vertical line, x = 2. Its vertex is located at the point (2, 0).
The line of symmetry of y = 0 is x = 0.