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Vertex = (0,0)

Line of symmetry = y axis

You should of known that as this function is only X^2

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What is the line of symmetry of fx equals 5xsquared?

It has y-axis symmetry. anyfunction with only x^2 and its coefficient has y-axis. These are called even fuctions. Therefore, it also might be called evensymmetry.


What is the line of symmetry and the vertex when y equals 3x squared plus 2x minus 1?

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Forget about thw value of pi because it has nothing to do with the question. y = x2-8x+1 can be expressed as y = (x-4)2-15 Information about the vertex and line of symmetry can be extracted from the rearranged equation such as:- Vertex: (4, -15) Line of symmetry: x = 4


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A line of symmetry must go from one vertex to the midpoint of the opposite side.


What are the vertex and the axis of symmetry of the equation y equals 2x² plus 4x - 10?

In the form y = ax² + bx + c the axis of symmetry is given by the line x = -b/2a The axis of symmetry runs through the vertex, and the vertex is given by (-b/2a, -b²/4a + c). For y = 2x² + 4x - 10: → axis of symmetry is x = -4/(2×2) = -4/4 = -1 → vertex = (-1, -4²/(4×2) - 10) = (-1, -16/8 - 10) = (-1, -12)


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