If you mean: (x+5)^2 + (y+3)^2 = 16
Then its center is at (-5, -3) and its radius is 4
If the radius of a circle is 8, then the diameter is 16. The diameter of a circle is two times of a radius The equation would be d = 2r so plugging in 8 for r, the equation would become d = 2(8) Therefore d is 16.
Equation of circle: x^2 +y^2 -4x -6y -3 = 0 Completing the squares: (x-2)^2 +(y-3)^2 = 16 square units Therefore center of circle is at (2, 3) and its radius is 4 units
The equation is: (x+3)^2 +(y+5)^2 = 16
The radius of a circle is half of the diameter. Therefore, if the diameter is 16 inches, the radius would be half of 16, which is 8 inches. The radius is the distance from the center of the circle to any point on the circle's circumference.
x² + y² = 9/16 or 16x² + 16y² = 9
center 5,-3 radius 4
It is: (x+3)^2 + (y-5)^2 = 16
(x-0)² + (y-0)² = r²
If that equals 16 then the radius is 4
It is: (x-2)^2 +(y-7)^2 = 16
(x - 9)2 + (y + 5)2 = 16
You are describing a circle, with its center at the origin and a radius of 4 (the square root of 16)
x2 + y2= 16
4
If the radius of a circle is 8, then the diameter is 16. The diameter of a circle is two times of a radius The equation would be d = 2r so plugging in 8 for r, the equation would become d = 2(8) Therefore d is 16.
(x-2)^2 +(y-3)^2 = 16
x² + y² = 16.