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What is the domain of x squared plus y squared equals thirty six?
The graph is a circle with a radius of 6, centered at the origin
How do you construct circle graphs?
there is actually multiple ways to do this. the easiest way is to use this formula (x - h)² + (y - k)² = r² r is the radius, h is the x-poss( how far left or right the center of the circle is from the orgin), k is the y-poss(how far up or down the circle is). keep x and y as x and y just like you will do when graphing a line using y = mx + b example: (x - 3)2 + (y - k)2 = 25 note: not all graphing calculators can graph a circle. mine will graph half a circle instead. this websight has a hands on circle graph that you can test out, it also has practice problems: http://www.mathwarehouse.com/geometry/circle/equation-of-a-circle.php for more advanced users, you can graph a circle using polar cordinates instead. if you don't know what these are, you don't have to worry about this. to graph a circle using polar cordinants use this orderd pair (radius,theta) and make the the radius whatever you want the radius of the circle to be. keep theta as theta, if you make this a number you will graph a point. this will make a circle with it's center on the organ. example: (3,theta)
How do you write an equation for a circle graph with center at (-42) and radius 5?
The general form of the equation passing through the point (a,b) is (x-a)^2 + (y-b)^2=r^2 where ^2 means to the power of 2 or squared. So insert the point (-4,2) and radius, 5 is: (x+4)^2 + (y-2)^2=25
What kind of equation gives a circle on a graph?
x2 + y2 = r2 gives a circle centred on the origin, radius r.
How do you graph x squared plus y squared equals 15?
Well, darling, that's the equation of a circle with radius √15 centered at the origin. To graph it, just draw a nice little circle with a radius of about 3.87 units. And there you have it, a perfect circle to add some pizzazz to your math class.
