x2 + y2 + 6x + 8y - 24 = 0 add 32, 42, and 24 to both sides to complete the squares
(x2 + 6x + 32) + (y2 + 8y + 42) = 9 + 16 + 24
(x + 3)2 + (y + 4)2 = 49
[x - (-3)]2 + [y - (-4)]2 = 72
Center: (-3, -4)
Radius: 7
The graph is a circle with a radius of 6, centered at the origin
there is actually multiple ways to do this. the easiest way is to use this formula (x - h)² + (y - k)² = r² r is the radius, h is the x-poss( how far left or right the center of the circle is from the orgin), k is the y-poss(how far up or down the circle is). keep x and y as x and y just like you will do when graphing a line using y = mx + b example: (x - 3)2 + (y - k)2 = 25 note: not all graphing calculators can graph a circle. mine will graph half a circle instead. this websight has a hands on circle graph that you can test out, it also has practice problems: http://www.mathwarehouse.com/geometry/circle/equation-of-a-circle.php for more advanced users, you can graph a circle using polar cordinates instead. if you don't know what these are, you don't have to worry about this. to graph a circle using polar cordinants use this orderd pair (radius,theta) and make the the radius whatever you want the radius of the circle to be. keep theta as theta, if you make this a number you will graph a point. this will make a circle with it's center on the organ. example: (3,theta)
The general form of the equation passing through the point (a,b) is (x-a)^2 + (y-b)^2=r^2 where ^2 means to the power of 2 or squared. So insert the point (-4,2) and radius, 5 is: (x+4)^2 + (y-2)^2=25
x2 + y2 = r2 gives a circle centred on the origin, radius r.
The graph of that equation is a circle, centered at the origin, with radius = 2 .
You are describing a circle, with its center at the origin and a radius of 4 (the square root of 16)
The graph is a circle with a radius of 6, centered at the origin.
The graph is a circle with a radius of 6, centered at the origin
Draw a circle with its center at the origin and a radius of 3.
There are two common ways to graph circles: using a cartesian graph and using a polar graph. For a cartesian graph, there are two familiar axes x and y which are orthogonal to each other. The formula for a circle is "x^2 + y^2 = a constant". In a polar graph, there are no axes and all points are defined by their radius from the center point, and the angle of the direction the point lies from the center. In a polar coordinate system, a circle is simply "r = a constant".
Any point on the graph can be the center of a circle. If the center is on the x-axis, then the circle is symmetric with respect to the x-axis.
It is a graph of all points which are are the same distance (the radius) from a fixed point (the centre).
there is actually multiple ways to do this. the easiest way is to use this formula (x - h)² + (y - k)² = r² r is the radius, h is the x-poss( how far left or right the center of the circle is from the orgin), k is the y-poss(how far up or down the circle is). keep x and y as x and y just like you will do when graphing a line using y = mx + b example: (x - 3)2 + (y - k)2 = 25 note: not all graphing calculators can graph a circle. mine will graph half a circle instead. this websight has a hands on circle graph that you can test out, it also has practice problems: http://www.mathwarehouse.com/geometry/circle/equation-of-a-circle.php for more advanced users, you can graph a circle using polar cordinates instead. if you don't know what these are, you don't have to worry about this. to graph a circle using polar cordinants use this orderd pair (radius,theta) and make the the radius whatever you want the radius of the circle to be. keep theta as theta, if you make this a number you will graph a point. this will make a circle with it's center on the organ. example: (3,theta)
x^(2) + y^(2) = 36 = 6^(2) The graph is a circle of radius '6' , centred on the origin (0,0).
The general form of the equation passing through the point (a,b) is (x-a)^2 + (y-b)^2=r^2 where ^2 means to the power of 2 or squared. So insert the point (-4,2) and radius, 5 is: (x+4)^2 + (y-2)^2=25
The general form of the equation passing through the point (a,b) is (x-a)^2 + (y-b)^2=r^2 where ^2 means to the power of 2 or squared. So insert the point (-4,2) and radius, 5 is: (x+4)^2 + (y-2)^2=25
x2 + y2 = r2 gives a circle centred on the origin, radius r.