answersLogoWhite

0

The center of a 29 x 50 rectangle can be found by dividing its length and width by two. The center point is located at (14.5, 25), where 14.5 is half of 29 and 25 is half of 50. Thus, the coordinates of the center are (14.5, 25).

User Avatar

AnswerBot

5d ago

What else can I help you with?

Related Questions

What is the Formula for center of gravity of a rectangle?

The formula for the center of gravity of a rectangle is: X = (W/2) and Y = (H/2), where X is the distance from the side of the rectangle to the center and Y is the distance from the top of the rectangle to the center, W is the width of the rectangle, and H is the height of the rectangle.


The perimeter of a rectangle is 50 centimeters The length of the rectangle is 20 centimeters What is the width of the rectangle?

Let the width be x: 2(length+width) = perimeter 2(20+x) = 50 40+2x = 50 2x = 50 -40 2x = 10 x = 5 centimeters Check: 5+5+20+20 = 50 centimeters


How do you write 3 and 29 over 50 as a percentage?

3 and 29/50 is the same as 358%= 3 29/50= 179/50 x 100%= 3.58 x 100%= 358%


What is the diagonal of a 50'x 20' rectangle?

53.85164807' by means of Pythagoras.


If MNOP is a rectangle and mMPN equals 50 what is the value of x?

80


What is the area of a rectangle that is 20cm tall and 50cm wide?

The area of a rectangle is 20 x 50 = 1,000 cm^2


What is the hypotenuse of a 50 x 60 rectangle?

A rectangle doesn't have a hypotenuse.The diagonal of this one is sqrt(6,100) = 78.1025 (rounded)


Is 26ft by 28ft smaller than 47ft by 12ft?

No, a rectangle measuring 26' x 28' has 29% more area than a rectangle measuring 47' x 12'.


What is the area of a rectangle if the length is 10ft and the width is 5ft?

Area of a rectangle = (length) x (width) = 10-ft x 5-ft = 50 square feet


The perimeter of a rectangle is 130m. The length of the rectangle is 25m more than the width. What are the lengths and widths of the rectangle?

x=width x+25=length 4x+50=130 4x=80 x=20 width is 20 length is 45


What are the dimensions of a rectangle that has a perimeter of 102 and an area of 50?

50' in Length by 1' in Width...50 x 1 = 50 :: 50+50+1+1=102


What is the area of a rectangle with a width of 50 feet and a length of 125 feet?

area = length x width = 125 x 50 = 6250 square feet