-4x2 + 9y2 + 16x - 18y +29 = 0 (I hope this is what you meant)
9y2 - 18y - (4x2 -16x) +29 = 0 (group together the x's and y's, and make the x2 term positive.
9(y2 - 2y) - 4(x2 - 4x) +29 = 0 (remove common factors)
9(y - 1)2 - 1 - 4(x - 2)2 - 4 + 29 = 0 (complete the squares)
9(y - 1)2 - 4(x - 2)2 = -25 (move constants to right-hand side)
[(y - 1)2] - 4[(x - 2)2]/9 = -25/9 (divide by coefficient in front of x or y bracket, in this case 9)
[(y - 1)2]/4 - [(x - 2)2]/9 = -25/36 (divide by coefficient in front of other bracket, in this case 4)
As you can see, we now have our equation in standard form. Our center points satisfy [(x - 2 = 0) , (y - 1 = 0)], thus our center is (2,1).
hyperbola
Center is (0, 0) . . . the origin.Radius is 7.
At the center, (x, y) = (-2, 5)
At the center, (x, y) = (-2, 5)
This not a circle, both the squared terms must have the same coefficients if it might be a circle. Different signs indicate a hyperbola.
It's an hyperbola equation.
hyperbola
y2 - 5y + 2x - x2 - 120 is not a circle. It is a hyperbola rotated through 90 degrees.
56
Center is (0, 0) . . . the origin.Radius is 7.
At the center, (x, y) = (-2, 5)
At the center, (x, y) = (-2, 5)
At the center, (x, y) = (-2, 5)
This not a circle, both the squared terms must have the same coefficients if it might be a circle. Different signs indicate a hyperbola.
(-4,-6)
(-7,5)
(-4,3)